One-way analysis of variance
For k groups let B=Σnᵢ(x̄ᵢ−x̄)² and W=Σᵢⱼ(xᵢⱼ−x̄ᵢ)².
Key knowledge
For k groups let B=Σnᵢ(x̄ᵢ−x̄)² and W=Σᵢⱼ(xᵢⱼ−x̄ᵢ)². Under equal means, independent normal observations with common variance give F=[B/(k−1)]/[W/(n−k)] the F_(k−1,n−k) law; reject for large F.
Conditions and scope
- k≥2, each group nonempty, total n>k and common variance positive; x̄ is the overall mean.
- This is an omnibus equal-means test; rejection does not identify every differing pair. Check residuals and adjust follow-up multiplicity.
Sources · 2
References
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Evidence and review
STAT500 sections 10.2.1–10.2.2 assumptions, sums of squares and table; STAT200 sections 10.1–10.2 F degrees of freedom and upper-tail calibration.
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