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Chemistry · Lesson

Mass spectrometry, ionisation and fragmentation

Follow the ion produced and the charge assigned before interpreting a mass-spectrometric axis. Keep nominal mass, isotope patterns, peak widths and formal fragments within their evidence limits.

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By the end, you can

  • Calculate a spectral-axis value for assigned protonated charge states.
  • Distinguish an FWHM resolving-power value from centroid error.
  • Calculate a purely synthetic isotope envelope from stipulated probabilities.
  • Balance a formal fragment net without claiming that it actually occurs.
01

The detector observes an ion produced by a defined process

Mass spectrometry produces and observes ions. Electron ionization, electrospray and other ionization processes have different mechanisms and can give different charge states, adducts or fragments. The neutral material originally present and the detected ion need not have the same formula, charge or mass.

For the spectral-axis convention used here, define ξ=(m_ion/u)/|z|, where m_ion is ion mass, u the unified atomic mass unit and z the signed charge number. The axis value is dimensionless after normalizing mass by u and dividing by the magnitude of charge number. Familiar “m/z” notation requires this convention to be understood; dividing by signed z would place a negative ion incorrectly on a negative mass axis.

Historical terminology can differ. An older Gold Book entry used mass-number wording, while the 2013 IUPAC recommendation defines its axis through ion mass/u and absolute charge number. Mass number is an integer nucleon count; it should not replace a specified isotope-dependent ion mass in the present calculations. Exact mass is calculated for specified isotopes, while accurate mass refers to a measurement.

02

Adduct and charge assignments determine the neutral-mass inference

An invented neutral entity M has assigned mass 1000.00000 u. Use rounded proton mass 1.00728 u in an explicitly additive mass model. Assigned [M+H]⁺ has ion mass 1001.00728 u and ξ=1001.00728. Assigned [M+2H]²⁺ has ion mass 1002.01456 u and ξ=501.00728.

The second ion is heavier than the first even though its axis value is about half as large. Reverse calculation for the doubly charged assignment gives neutral mass |z|ξ u−2m_proton=1000.00000 u. It relies on the stated adduct and charge, not axis position alone. Proton addition is different from adding a neutral hydrogen atom; the latter includes an electron.

Assign a synthetic isotope mass increment 1.0034 u. Its corresponding axis spacing is 1.0034 for a singly charged ion and 0.5017 for a doubly charged ion. The inputs are hypothetical and rounded, with binding-energy mass corrections omitted from the additive model. Charge/adduct assignments and any real isotope interpretation need their own evidence.

03

A narrower peak does not remove a centroid error

State the width criterion when reporting a resolving-power value. Here define FWHM resolving power R_FWHM=ξ/Δξ_FWHM, with full width at half maximum at the specified axis position. A different peak-width or valley criterion is a different convention and cannot be converted universally without a suitable peak model.

Give hypothetical ξ=500 and FWHM 0.0250. Then R_FWHM=20000. Separately, let a measured teaching input centroid be 500.005 while the known reference value is 500.000. Signed relative centroid error is 10⁶(500.005−500.000)/500.000=+10.0 ppm. These are invented inputs, not an instrument performance test.

Halving FWHM to 0.0125 doubles R_FWHM to 40000, but leaving that same centroid leaves the +10.0 ppm error unchanged. Precision, calibration, error, peak width and separation of two different ions are related practical concerns with different definitions. A width number alone does not guarantee a unique formula or two-peak separability.

04

An isotope envelope needs probability and response assumptions

Use fictional site label X, which does not denote an actual chemical element. Stipulate two independent X sites, each having light-state probability 0.750 and heavy-state probability 0.250, with assigned heavy mass increment 2.00 u. Suppose all resulting forms have equal detector response per entity and charge magnitude one.

The grouped probabilities for zero, one and two heavy sites are (0.75)²=0.5625, 2×0.75×0.25=0.3750 and (0.25)²=0.0625. They sum to one and give relative ratio 9:6:1 at assigned mass offsets 0, 2 and 4 u. The middle group contains two distinct site assignments, light–heavy and heavy–light.

Expected heavy-site count is 2×0.25=0.500. The plot shows this synthetic probability distribution against heavy-site count, not an actual mass spectrum or measured isotope intensities. It makes no chlorine, bromine or other natural-abundance assignment and cannot uniquely identify a real molecule.

A synthetic two-site isotope probability model

Grouped probability

Fictional X sites each independently have heavy-state probability 0.250. Circle markers show the grouped probabilities for zero, one or two heavy sites; there is no continuous distribution or fitted curve. Assigned heavy mass increment 2.00 u gives offsets 0, 2 and 4 u for charge magnitude one. Equal per-entity response is stipulated. These are calculated probabilities, not real isotope abundances or a mass spectrum.01200.1560.3130.4690.625

Number of heavy X sites

  • Assigned two-site probabilities
Underlying data
Number of heavy X sitesGrouped probability
00.5625 · Assigned two-site probabilities
10.375 · Assigned two-site probabilities
20.0625 · Assigned two-site probabilities

Fictional X sites each independently have heavy-state probability 0.250. Circle markers show the grouped probabilities for zero, one or two heavy sites; there is no continuous distribution or fitted curve. Assigned heavy mass increment 2.00 u gives offsets 0, 2 and 4 u for charge magnitude one. Equal per-entity response is stipulated. These are calculated probabilities, not real isotope abundances or a mass spectrum.

05

Conservation is necessary but does not establish a fragment pathway

A formal net can be tested without claiming that it is observed. Choose precursor radical cation C₃H₆O⁺• and products C₂H₃O⁺ plus neutral methyl radical CH₃•. The selected net conserves C, H and O atoms and total charge +1.

Using assigned nominal atom masses C=12, H=1 and O=16, the nominal masses are 58, 43 and 15, and 58=43+15. Electron counts from atomic numbers and charge are 31 for the precursor, 22 for the charged product and 9 for the neutral radical, again closing the ledger. An odd-electron precursor is consistent with these chosen even-electron and radical products.

These are formal entity and nominal-mass inventories. They do not demonstrate a measured peak, actual fragmentation mechanism, preferred channel, complete reaction or an accurate/average mass result. Alternative balanced nets can exist. Chemical context and observed complementary evidence are required to identify a real pathway.

06

A plausible assignment still needs discrimination from alternatives

An axis value, isotope pattern or fragment can constrain an assignment, but isomers and alternative ion forms can share some observations. Sample preparation, separation, ionization and response should be traced to the chemical entity and quantity being reported.

Combine appropriate calibrated measurements and references, retaining uncertainty and unresolved candidates. This lesson uses hypothetical masses and probabilities and selected formal formula ledgers; it imports no reference spectra, operating settings or measured structural identification.

Worked examples

Separate ion mass from axis position

Use neutral M mass 1000.00000 u and rounded proton mass 1.00728 u.

  1. [M+H]⁺ mass and axis are 1001.00728 u and 1001.00728.
  2. [M+2H]²⁺ mass is 1002.01456 u, while its axis is 501.00728.
  3. The synthetic isotope increment 1.0034 u gives doubly charged axis spacing 0.5017.

The assigned charge divisor changes the axis without halving ion mass.

Compare peak width and centroid error

Use axis 500, FWHM 0.0250, reference 500.000 and centroid 500.005.

  1. R_FWHM=500/0.0250=20000.
  2. Signed relative centroid error is +10.0 ppm.
  3. Halving width alone doubles resolving power and leaves that error unchanged.

The width criterion and position are separate from centroid agreement.

Group the independent site assignments

Use two fictional X sites with heavy probability 0.250 each.

  1. Light–light probability is 0.5625.
  2. Light–heavy and heavy–light each give 0.1875, totaling 0.3750.
  3. Heavy–heavy probability is 0.0625; grouped ratio is 9:6:1.

A normalized invented envelope under stated equal-response assumptions.

Check a formal charged fragmentation ledger

Use C₃H₆O⁺•→C₂H₃O⁺+CH₃• with assigned nominal masses 12/1/16 for C/H/O.

  1. Atom counts and total +1 charge are equal on both sides.
  2. Nominal masses close as 58=43+15.
  3. Electron counts close as 31=22+9.

Conservation permits this formal net but does not prove its occurrence.

Try it yourself

  1. Assign [M+3H]³⁺ using the same neutral and proton masses and isotope increment. Find axis value and isotope axis spacing.

    Show the answer and reasoning

    334.340613 and 0.334466667.

    Ion mass is 1003.02184 u; divide its mass/u and the 1.0034 increment by charge magnitude three.

  2. Keep the hypothetical centroid 500.005 and reference 500.000 but halve FWHM to 0.0125. What changes and what stays fixed?

    Show the answer and reasoning

    R_FWHM becomes 40000; signed centroid error stays +10.0 ppm.

    The narrower width changes the width-based quotient, while the fixed reference difference leaves the relative error unchanged.

  3. Use one fictional X site with the same heavy probability 0.250. Give the two grouped probabilities and assigned mass offsets.

    Show the answer and reasoning

    0.750 and 0.250, ratio 3:1, at offsets 0 and 2 u.

    The one-site possibilities are exhaustive; the two-site binomial multiplicity no longer applies.

  4. Can formal H₂O loss from C₃H₆O⁺• conserve atoms, charge and electrons? Name the remaining ion and nominal mass, then state the inference limit.

    Show the answer and reasoning

    C₃H₄⁺• at nominal mass 40, plus H₂O at 18; the ledger balances but occurrence is unproven.

    Atoms and +1 charge are retained; electron counts 31=21+10 also close. A balanced alternative is not an observed pathway.

What to carry forward

  • Specify the detected ion, adduct and charge.
  • Normalize ion mass by u and divide by absolute charge number in the declared axis convention.
  • Accompany resolving power with its width criterion and position.
  • An isotope model requires stated probabilities and response assumptions.
  • Formal atom and electron conservation does not establish observed fragmentation.

References

Teaching resources and reference material supporting this lesson’s explanations and examples.

  1. Definitions of terms relating to mass spectrometryKermit K. Murray, Louisiana State University USA; Robert K. Boyd, NRC Canada; Marcos N. Eberlin, UNICAMP Brazil; G. John Langley, Southampton UK; Liang Li, Alberta Canada; Yasuhide Naito, Hamamatsu JapanSourcepublications.iupac.orgRead source
  2. IUPAC Gold Book: historical mass-to-charge ratioIUPAC Gold Book Joint Subcommittee; original recommendation identified in inspected entrySourcegoldbook.iupac.orgRead source
  3. CODATA 2022 proton mass in uNIST Fundamental Physical Constants; CODATA task groupSourcephysics.nist.govRead source
  4. The Fitness for Purpose of Analytical MethodsH. Cantwell, editor; Eurachem Method Validation Working GroupSource · PDFeurachem.orgRead source