Chemistry · Lesson
Gas, liquid and other chromatographic methods
Compare chromatographic mechanisms through analyte compatibility and interactions. Use a scoped transport model, a defined flow basis and an accessible-volume model without turning them into universal performance rankings.
Back to the Chemistry mapBy the end, you can
- Match gas or liquid chromatography candidates to stated chemical and detector conditions.
- Calculate a synthetic plate-height minimum with consistent units.
- Distinguish superficial and interstitial velocity.
- Use size-exclusion and form-specific retention models within their assumptions.
A method name does not establish compatibility
Gas chromatography uses a gaseous mobile phase; appropriate analytes must be transferable and sufficiently stable under the particular conditions. Liquid chromatography uses a liquid mobile phase and suitable stationary interactions. Solubility, chemical form, stability, matrix, phase compatibility and detector response all matter. Neither name guarantees a separation or a quantitative result.
A hypothetical constituent X is stipulated to be insufficiently volatile and to transform under a proposed direct-GC method, while remaining soluble and stable in a given LC medium with a calibrated detector response. The proposed direct-GC option is incompatible with the stated X conditions. LC is a candidate requiring selectivity and procedure validation, not an automatically successful solution.
A different hypothetical Y is volatile and stable in a proposed GC method but gives no response in the proposed ultraviolet channel. Those separation prerequisites do not repair the missing detector response. Derivatization may improve suitability in some methods, but it changes the measured entity and introduces conversion and recovery questions. No actual substances or operating programs are assigned here.
The phase interaction supplies selectivity
Adsorption emphasizes interaction with a surface; partition describes distribution between phases. Ion-exchange retention depends on ionic interactions and the relevant chemical forms and competing ions. Size-exclusion chromatography emphasizes access to pore volume under conditions that minimize other interactions. Real stationary phases can combine mechanisms.
In LC, an isocratic method maintains the stipulated mobile-phase composition, while a gradient changes composition over time. Such changes can alter retention and response, so a constant-k equilibrium model should not be transplanted unchanged into a gradient. In GC, temperature and gas-pressure conventions affect time, volume and velocity comparisons.
A retention index compares an analyte with a specified reference series under a defined convention. For an isothermal Kováts index, logarithms of adjusted retention times are used between bracketing normal alkanes. Temperature-programmed linear indices use a different relation. Reference normalization improves a comparison’s structure but does not make it unique identity evidence or independent of method conditions.
A plate-height minimum depends on the chosen model
A simple packed-column van Deemter model is H=A+B/u+Cu, where u is the explicitly chosen linear velocity and H is plate height. The terms represent different contributions to band broadening within that model. A, B and C are not universal constants: analyte, phase, temperature and geometry influence them.
Assign hypothetical A=0.0200 mm, B=0.0600 mm² s⁻¹ and C=0.00500 s. With u in mm s⁻¹, all three terms have mm units. The model minimum occurs at u*=√(B/C)=3.46410 mm s⁻¹, where H*=A+2√(BC)=0.0546410 mm. The low-velocity B/u term and high-velocity Cu term are equal at this point.
For an assigned L=150 mm, N=L/H*=2745.19. If this toy treats u as the appropriate mobile passage velocity and k=3.00, t_M=L/u*=43.3013 s and t_R=(1+k)t_M=173.205 s. The calculation does not optimize a real column, pressure, gradient, compressible flow or extra-column contribution. Faster motion alone can increase the Cu contribution.
Plate height / mm
Chosen velocity / mm s⁻¹
- Selected calculated plate heights
- — Assigned H=A+B/u+Cu equation
Underlying data
| Chosen velocity / mm s⁻¹ | Plate height / mm |
|---|---|
| 0.5 | 0.1425 · Selected calculated plate heights |
| 1 | 0.085 · Selected calculated plate heights |
| 2 | 0.060000000000000005 · Selected calculated plate heights |
| 3 | 0.055 · Selected calculated plate heights |
| 3.4641016151377544 | 0.05464101615137755 · Selected calculated plate heights |
| 4 | 0.05500000000000001 · Selected calculated plate heights |
| 6 | 0.06 · Selected calculated plate heights |
| 8 | 0.0675 · Selected calculated plate heights |
Original packed-column teaching model H=0.0200 mm+(0.0600 mm² s⁻¹)/u+(0.00500 s)u. Circle markers are selected calculated points; the dashed curve samples the same equation. Model constants and the velocity definition are held fixed. The minimum is 0.0546410 mm at 3.46410 mm s⁻¹. No measured instrument performance or operating recommendation is represented.
Volume flow and linear velocity have different meanings
A volume flow rate F divided by the full column cross-sectional area gives a superficial velocity u_s=F/A_cross. If only an assigned fraction ε of that area is available to interparticle flow, an interstitial definition gives u_i=F/(εA_cross). These are different bases for the same volume flow. A transport equation must state which one its parameters use.
In a pure unit and geometry exercise, stipulate incompressible F=0.600 mL min⁻¹, diameter 1.00 mm and interparticle porosity ε=0.400. Flow is 10.0 mm³ s⁻¹ and cross-sectional area is π/4=0.785398 mm². Superficial velocity is 12.7324 mm s⁻¹; interstitial velocity is 31.8310 mm s⁻¹.
Total accessible mobile volume in porous particles can require another volume definition. A GC volume flow also needs the relevant temperature and pressure conventions. These numerical inputs supply geometry, not evidence that a particular column or pressure is usable. They are separate from the previous plate-height example.
A size-exclusion model tracks accessible volume
For an ideal size-exclusion volume model, V_e=V_0+K_access V_i. Here V_e is retention volume, V_0 is outside-pore mobile volume and V_i is the fully accessible pore volume. The coefficient K_access lies between zero and one in this restricted model. Excluded solutes approach V_0; fully accessing solutes approach V_0+V_i.
Assign V_0=11.0 mL and total fully accessible mobile volume V_t=31.0 mL, so V_i=20.0 mL. For observed hypothetical V_e=23.0 mL, K_access=(23−11)/20=0.600. The formula describes pore-volume access rather than directly providing a molecular mass. Size, shape, calibration chemistry and non-size interactions affect interpretation.
A stipulated comparison at V_e=9.00 mL would give K_access=−0.100. That is outside the assigned pure access model; it is not a negative molecular size. Additional delay conventions, exclusion anomalies, interactions or a wrong volume reference would need investigation rather than silently accepting the model.
An average retention factor uses mobile-form fractions
Suppose symbolic HA and A⁻ interconvert rapidly in the mobile phase. In an ideal model with fixed form-specific k_HA and k_A, stationary inventory is the sum k_HA n_HA,m+k_A n_A,m. Dividing by total mobile inventory gives apparent k=f_HA,m k_HA+f_A,m k_A. The weights are mobile-phase fractions, not fractions of the whole mobile-plus-stationary inventory.
Assign ideal pK_a=6.00 with activity coefficients one and standard concentration 1 mol L⁻¹, k_HA=4.00 and k_A=0.500. At pH 5, 6 and 7, the neutral mobile fractions are 10/11, 1/2 and 1/11. Apparent k values are 3.68182, 2.25000 and 0.818182. This example deliberately holds solvent, temperature, ionic environment, stationary phase and form-specific k values fixed.
Real pH changes can also change surface charge and other interactions. The decreasing trend in this invented case is not universal, and it is not a GC prediction. Method choice requires the actual forms and mechanism, not a broad rule based only on a method label or a solute charge.
Worked examples
Find the assigned transport minimum
Use A=0.0200 mm, B=0.0600 mm² s⁻¹, C=0.00500 s and L=150 mm.
- u*=√(B/C)=√12=3.46410 mm s⁻¹.
- H*=0.0200+2√(0.0600×0.00500)=0.0546410 mm.
- N=2745.19; in the stated passage model t_M=43.3013 s and at k=3.00, t_R=173.205 s.
A minimum in the stipulated model, rather than a tested instrument setting.
Declare the flow-area basis
Use F=0.600 mL min⁻¹, diameter 1.00 mm and ε=0.400.
- F=10.0 mm³ s⁻¹ and A_cross=0.785398 mm².
- u_s=10.0/0.785398=12.7324 mm s⁻¹.
- u_i=u_s/0.400=31.8310 mm s⁻¹.
One volume flow gives two velocities with different area definitions.
Calculate a pore-access fraction
Use V_0=11.0 mL, V_t=31.0 mL and V_e=23.0 mL.
- The accessible pore volume is V_i=20.0 mL.
- K_access=(23−11)/20=0.600.
- A comparison V_e=9.00 mL gives −0.100, outside this pure access model.
The coefficient describes the assigned volume model, not an inferred negative size.
Weight retention by mobile-form inventories
Use pH=pK_a=6.00 and given k_HA=4.00, k_A=0.500.
- The mobile phase has equal ideal HA and A⁻ fractions.
- Apparent k=0.5×4.00+0.5×0.500=2.25000.
- For a 1.00 mmol total mobile inventory, stationary amount is 2.00+0.250=2.250 mmol.
The weights belong to the mobile inventory and the stipulated rapid-exchange model.
Try it yourself
In the same H model, evaluate H at u=2.00 mm s⁻¹ and calculate N for L=150 mm.
Show the answer and reasoning
H=0.0600 mm; N=2500.
The three contributions are 0.0200, 0.0300 and 0.0100 mm. Divide 150 mm by their sum.
Keep V_0=11.0 mL and V_t=31.0 mL but assign V_e=21.0 mL. Find K_access.
Show the answer and reasoning
0.500.
The solute accesses 10.0 mL of the assigned 20.0 mL pore volume in this model.
Hypothetical X transforms under a proposed direct-GC method but is stable and soluble in a stated LC medium with calibrated response. What conclusion follows?
Show the answer and reasoning
The proposed direct-GC option is incompatible; LC is a candidate requiring selectivity and full-procedure validation.
Solubility and response prerequisites do not yet show that LC separates X from relevant matrix constituents or measures the intended quantity reliably.
Why is an apparent k calculated from the mobile-form fractions rather than simply averaging fractions of the whole phase inventory?
Show the answer and reasoning
k is stationary amount divided by mobile amount.
Each stationary-form amount is its form-specific k times its mobile-form amount. Summing those amounts and dividing by total mobile amount gives mobile-fraction weights.
What to carry forward
- Match analyte, medium, stationary interactions and detector response.
- Temperature, composition and pressure conventions affect retention comparisons.
- A transport minimum belongs to specified constants and a velocity definition.
- Accessible-volume coefficients require a compatible size-exclusion model.
- Rapid-exchange apparent retention uses mobile-form inventory weights.
References
Teaching resources and reference material supporting this lesson’s explanations and examples.
David T. Harvey, DePauw University, USA5 sources
- Analytical Chemistry 2.1: 12.4 Gas ChromatographyDavid T. Harvey, DePauw University, USASource
- Analytical Chemistry 2.1: 12.5 High-Performance Liquid ChromatographyDavid T. Harvey, DePauw University, USASource
- Analytical Chemistry 2.1: 12.6 Other Forms of ChromatographyDavid T. Harvey, DePauw University, USASource
- Analytical Chemistry 2.1: 12.2 General Theory of Column ChromatographyDavid T. Harvey, DePauw University, USASource
- Analytical Chemistry 2.1: 12.3 Optimizing Chromatographic SeparationsDavid T. Harvey, DePauw University, USASource
IUPAC Gold Book Joint Subcommittee; original recommendation identified in entry3 sources
- IUPAC Gold Book: plate heightIUPAC Gold Book Joint Subcommittee; original recommendation identified in entrySource
- IUPAC Gold Book: retention index in column chromatographyIUPAC Gold Book Joint Subcommittee; original recommendation identified in entrySource
- IUPAC Gold Book: distribution ratio in liquid–liquid distributionIUPAC Gold Book Joint Subcommittee; original recommendation identified in entrySource
- IUPAC: Definitions of terms and symbols used in gas chromatographyJosé Antonio García Domínguez; José Carlos Díez-Masa; CSIC, SpainSource
- University of Sheffield: Chromatography serviceUniversity of Sheffield School of Mathematical and Physical Sciences, UK; institutional service pageSource