GLOBAL KNOWLEDGE ARK

Cosmology · Expansion history and cosmic bookkeeping

Conservation laws and their boundaries

Follow energy in an expanding region for three distinct ideal components, then distinguish local conservation from a single total energy assigned to the whole Universe.

Preparation: ratios, powers of ten and ordinary arithmetic. Physical quantities and notation are introduced as they are needed.

Back to the chapter

After reading, you can

  • Calculate energy from energy density and the specified following volume.
  • Apply the pressure–volume balance with the correct pressure behaviour.
  • Distinguish local stress-energy conservation from a global conservation claim requiring additional structure.
01

A conservation claim needs an account

When a photon redshifts, a comoving observer later measures less photon energy than a corresponding earlier comoving observer. Where did that energy go? Before inventing a destination, identify the quantity being compared, the observers and the region whose account is being kept.

Use the same homogeneous relativistic fluid description as the preceding lesson. Let q = a/a_ref and follow a region moving with the background fluid. Its proper volume is V = V_ref q³. Write its fluid energy as E = εV, with energy density ε in J/m³.

For a separately conserved ideal fluid, the continuity equation gives dE = −P dV, where P is pressure. This relates changes of energy and proper volume along the chosen expansion history. It does not require the region to be a literal container with material walls.

The equation is a form of the local fluid balance. Its use here assumes the stated homogeneous fluid, a following volume and no exchange with another component. Adding interactions or following a different boundary requires the corresponding terms and definitions.

02

The component’s pressure changes the result

Compare three separate hypothetical component accounts. In each case choose V_ref = 1 m³ and ε_ref = 8 J/m³ at q = 1. Each therefore starts with E_ref = 8 J. They are alternatives with the same reference numbers, not three descriptions of the same substance.

For conserved pressureless matter, ε = 8q⁻³ J/m³ and P is approximately zero. At q = 2, the volume is 8 m³ and ε = 1 J/m³, so E = 8 J. Dilution lowers the density while the rest-energy total in this following region stays fixed.

For separately conserved free radiation, ε = 8q⁻⁴ J/m³ and P = ε/3. At q = 2, ε = 1/2 J/m³ and E = 4 J. The photon energy total decreases as the volume grows; the pressure is positive and also changes during expansion.

For an ideal cosmological-constant component, ε = 8 J/m³ remains constant and P = −ε = −8 Pa. At q = 2, E = 64 J. The following volume contains more of this component’s energy because its energy density stays fixed while the volume increases. The negative pressure gives the corresponding sign in dE = −P dV.

Three separate ideal components with the same chosen reference energy density 8 J/m³ and reference volume 1 m³; values at q = 2
Separate componentε at q = 2P at q = 2Following volumeE at q = 2Change from 8 J
Pressureless matter1 J/m³Approximately 0 Pa8 m³8 J0 J
Free radiation1/2 J/m³1/6 Pa8 m³4 J−4 J
Cosmological constant8 J/m³−8 Pa8 m³64 J+56 J
Density dilution and following-region energy are different accountsThree separate ideal homogeneous component accounts each start with reference volume 1 m³ and reference energy density 8 J/m³ at q = a/a_ref = 1, so each starts with energy 8 J. The common following volume is V = q³ m³. On a linear q axis from 1 to 2 and a shared linear energy axis from 0 to 70 J, dotted blue pressureless-matter energy stays at 8 J, solid orange free-radiation energy 8/q falls to 4 J, and dashed green true cosmological-constant energy 8q³ rises to 64 J. A common circle marks the shared initial 8 J, with distinct endpoint diamond, circle and square markers and direct labels. At q = 2, V = 8 m³. These are alternative component accounts with different pressure behaviour, not a transfer among three substances. Radiation has changing P = ε/3 and ΔE = −4 J, matching −∫P dV with integral +4 J; the final pressure times the total volume change is insufficient. The constant-Lambda case has P = −8 Pa and ΔE = +56 J. The following region has no material walls, and the curves identify no external energy receiver or global conserved total.One expanding region, three separate ideal accountsV_ref = 1 m³; ε_ref = 8 J/m³ in each separate caseq = a/a_ref · V = q³ m³ · E = εVmatterradiationconstant ΛFollowing-region energy E (J)081632486464 Jmatter: 8 Jradiation: 4 J11.251.51.752Relative scale q (dimensionless)At q = 2, the following volume is 8 m³.Radiation: ΔE = −4 J and ∫P dV = +4 J.Constant Λ: P = −8 Pa and ΔE = +56 J.Radiation pressure changes; endpoint P × ΔV is insufficient.No conversion between the separate components is implied.The following surface is not a material container wall.
Three separate ideal homogeneous component accounts each start with reference volume 1 m³ and reference energy density 8 J/m³ at q = a/a_ref = 1, so each starts with energy 8 J. The common following volume is V = q³ m³. On a linear q axis from 1 to 2 and a shared linear energy axis from 0 to 70 J, dotted blue pressureless-matter energy stays at 8 J, solid orange free-radiation energy 8/q falls to 4 J, and dashed green true cosmological-constant energy 8q³ rises to 64 J. A common circle marks the shared initial 8 J, with distinct endpoint diamond, circle and square markers and direct labels. At q = 2, V = 8 m³. These are alternative component accounts with different pressure behaviour, not a transfer among three substances. Radiation has changing P = ε/3 and ΔE = −4 J, matching −∫P dV with integral +4 J; the final pressure times the total volume change is insufficient. The constant-Lambda case has P = −8 Pa and ΔE = +56 J. The following region has no material walls, and the curves identify no external energy receiver or global conserved total. Original Ark teaching model.
03

Endpoint pressure is not the whole history

For the radiation account, pressure falls during expansion. Multiplying its final pressure, 1/6 Pa, by the volume increase, 7 m³, would give 7/6 J. That is not the correct integrated pressure term, because the earlier pressure was larger.

The finite change is ΔE = −∫P dV along the history. Radiation gives ΔE = 4 J − 8 J = −4 J, so the integral of P dV is 4 J. A definite integral adds the contributions with the pressure appropriate to each intermediate volume.

An optional mathematical check writes E(V) = 8 J × (V/V_ref)⁻¹ᐟ³. Differentiation gives −dE/dV = [8 J/(3V_ref)] × (V/V_ref)⁻⁴ᐟ³, which is ε/3 and has pressure units. Integrating between V_ref and 8V_ref reproduces the 4 J decrease.

The cosmological-constant example is different because its pressure is constant. There ΔE = −PΔV = −(−8 Pa)(7 m³) = 56 J. The shortcut works because the pressure does not change over this particular interval, not because endpoint multiplication is a universal rule.

04

Local conservation remains valid

General relativity expresses local stress-energy conservation through a covariant divergence equation, often written ∇_μ T^{μν} = 0. The tensor notation is optional here: it states a local balance of energy and momentum using the spacetime geometry. The fluid continuity equation used above is its homogeneous energy-balance form.

A single total energy for an entire curved, evolving spacetime is an additional question. Constructing a conserved global energy requires appropriate structure, such as a suitable time-translation symmetry or specified boundary conditions and a valid definition of the associated charge.

A generic expanding cosmological background does not supply the same preferred time-translation symmetry as a stationary situation. One therefore cannot assume that adding locally measured photon energies on different cosmic-time slices produces a universal conserved scalar for the whole Universe.

This does not mean that energy conservation is meaningless or that energy is never conserved in general relativity. Local conservation applies, and global conserved quantities can exist when the required conditions hold. The lesson is to state those conditions before extending a local or familiar mechanical account to all of cosmology.

05

Do not create an unsupported destination

The radiation calculation establishes a particular result: the photon energy in a specified following region decreases as its volume expands, consistently with the local pressure–volume relation. It does not identify a separate reservoir receiving an equal amount of energy.

The cosmological-constant calculation is a separate ideal account. Combining its increasing energy with the radiation example does not show that redshift energy turns into dark energy. No such conversion law was assumed or derived.

Likewise, the chosen region’s boundary is a bookkeeping surface moving with the smooth fluid, not a physical piston. The pressure term has a precise place in the relativistic fluid balance; a picture of an external container can add mechanisms that are absent from the model.

A useful first-reading procedure is to ask: Which observers measure energy? Which region is followed? What are ε and P? Are there exchanges? Does a proposed global conservation statement have the extra structure it needs? These questions preserve the valid conservation law while exposing an unjustified extension.

Worked reasoning

Check the constant-pressure account

For the separate ideal cosmological-constant component, what energy change occurs when the following volume grows from 1 to 8 m³ with ε = 8 J/m³?

  1. Calculate the endpoints: E_initial = 8 J and E_final = 64 J, so ΔE = 56 J.
  2. Use the component’s pressure P = −8 Pa, which stays constant throughout the interval.
  3. The balance gives −PΔV = −(−8 Pa)(7 m³) = 56 J, matching the endpoints. No radiation-to-dark-energy transfer has been introduced.

The following-region energy increases by 56 J in this separate ideal account.

Try the reasoning

  1. Why is final radiation pressure times the total volume change insufficient in the stated example?

    Show the answer and reasoning

    Radiation pressure changes during the expansion.

    The finite pressure term must be integrated along the history; its value is 4 J, not 7/6 J.

  2. When the pressureless matter density falls from 8 to 1 J/m³, has the following-region rest energy fallen by a factor of eight?

    Show the answer and reasoning

    No. It remains 8 J in this approximation.

    The following volume increases from 1 to 8 m³, compensating the density decrease.

  3. Does local stress-energy conservation by itself establish one universally conserved total energy for every cosmological spacetime?

    Show the answer and reasoning

    No.

    A global conserved quantity requires a suitable definition and additional structure, such as the relevant symmetry or boundary conditions.

What to carry forward

  • For a separately conserved homogeneous fluid in a following volume, dE = −P dV.
  • Changing pressure requires an integral; density and following-region total energy are different quantities.
  • Local conservation remains valid while global conservation claims need their own definitions and conditions.

References

Sources supporting the explanations, physical distinctions and examples in this lesson.

  1. Sean M. Carroll3 sources
    1. Lecture Notes on General Relativity: 8 CosmologySean M. CarrollCourse notes · PDFpreposterousuniverse.comRead source
    2. Lecture Notes on General Relativity: 4 GravitationSean M. CarrollCourse notes · PDFpreposterousuniverse.comRead source
    3. Lecture Notes on General Relativity: 5 More GeometrySean M. CarrollCourse notes · PDFpreposterousuniverse.comRead source
  2. General Relativity: 4 The Einstein EquationsDavid TongCourse notesdamtp.cam.ac.ukRead source
  3. The International System of Units (SI)Bureau International des Poids et MesuresTeaching resource · PDFbipm.orgRead source