GLOBAL KNOWLEDGE ARK

Cosmology · Cosmic dark ages, first light and reionisation

The hydrogen 21-centimetre signal

Relate hyperfine populations to spin temperature and calculate absorption, zero contrast and emission from three supplied uniform slabs.

Preparation: ratios, powers of ten and ordinary arithmetic. Physical quantities and notation are introduced as they are needed.

Back to the chapter

After reading, you can

  • Distinguish spin temperature from gas kinetic temperature.
  • Calculate a signed line brightness contrast against a supplied background.
  • Keep redshift, optical depth and temperature assumptions explicit when interpreting a 21-centimetre example.
01

Spin temperature describes a level-population ratio

Neutral hydrogen has hyperfine levels whose transition produces radiation near the wavelength conventionally called 21 centimetres. The line can probe neutral gas through its contrast against a background radiation field.

Define spin temperature T_s by n_1/n_0 = 3exp(−T_*/T_s), where n_1 and n_0 are the upper and lower hyperfine populations and T_* = hν_0/k_B is the splitting expressed as a temperature. The factor three is the ratio of their statistical weights.

This definition describes the hyperfine population ratio. It does not set T_s equal to the gas kinetic temperature. Radiation, collisions and other coupling processes determine how those populations relate to the gas and radiation fields.

The supplied example uses positive spin temperatures well above T_* and a Rayleigh–Jeans brightness account. It does not solve the population coupling, heating or ionization history that would establish T_s in a real region.

02

Line emission and background attenuation contribute together

For a uniform-excitation slab with optical depth τ and background rest-frame brightness temperature T_R, use T_out,rest = T_s(1 − exp(−τ)) + T_R exp(−τ) in the stated Rayleigh–Jeans limit.

The first term is the slab’s contribution to the emergent brightness, while the second is the attenuated background. Subtracting the unattenuated background gives T_out,rest − T_R = (T_s − T_R)(1 − exp(−τ)).

Under cosmological redshift, the Rayleigh–Jeans brightness-temperature difference observed at the redshifted line frequency is ΔT_obs = (T_s − T_R)(1 − exp(−τ))/(1 + z). Both temperatures in the numerator are defined in the slab rest frame.

This is a difference relative to the redshifted background, not an absolute sky temperature. Its sign can be negative, zero or positive even though the supplied slab contains neutral hydrogen in every case.

03

Neutral gas can absorb, have zero contrast or emit

Choose T_R = 40 K, τ = 0.02 and z = 9. Compare separate prescribed uniform slabs with T_s = 10 K, 40 K and 80 K. The 40 K background is a teaching input, not an observed CMB temperature.

At T_s = 10 K, the slab is cooler in spin temperature than its background, giving ΔT_obs ≈ −59.4040 mK. At T_s = 80 K, the same transfer formula gives positive contrast of about 79.2053 mK.

When T_s = T_R = 40 K, emission and background attenuation exactly cancel in this line-contrast account. The output rest brightness remains 40 K and ΔT_obs is zero despite the nonzero supplied optical depth.

These rows are different prescribed slabs with a common τ. They do not follow one fixed-column parcel as it warms: maintaining τ while changing T_s can require different columns or line profiles. No such column evolution is calculated here.

Separate synthetic uniform slabs with rest-frame T_R = 40 K, τ = 0.02 and z = 9; observed line difference uses the factor 1/(1 + z)
Spin T_s (K)Output rest brightness (K)Observed ΔT (mK)Contrast relative to background
1039.405960−59.403980Absorption
40400Zero line contrast
8040.79205379.205307Emission
Three supplied neutral slabs with negative, zero and positive line contrastThe spin temperature specifies the hyperfine level-population ratio n_1/n_0 = 3 exp(−T_*/T_s), with T_* = hν_0/k_B, rather than equalling the gas kinetic temperature by definition. This Rayleigh–Jeans uniform-excitation example uses positive T_s well above T_*. Three separate prescribed slabs share chosen rest-frame background brightness T_R = 40 K, optical depth 0.02 and redshift z = 9. Their spin temperatures are 10, 40, 80 K. Uniform transfer gives T_out (rest) = T_s[1−exp(−τ)] + T_R exp(−τ). After subtracting the unattenuated background and redshifting brightness temperature, ΔT_obs = (T_s−T_R)[1−exp(−τ)]/(1+z). The graph has a linear spin-temperature abscissa in kelvin and a signed linear observed-contrast ordinate in millikelvin, with an explicit zero baseline. Discrete bars, not a time trajectory, give approximately −59.403980, 0, +79.205307 mK; circle endpoints mark absorption/emission and a diamond marks exact zero. Rest-frame outgoing brightnesses are 39.405960, 40, 40.792053 K. At T_s = T_R, emission replaces attenuation and the line contrast vanishes despite nonzero optical depth and neutral gas. Fixed τ across different T_s denotes separate prescribed slabs that may need different columns or line profiles; no one fixed-column cloud is followed as it heats. The 40 K background is supplied, not an observed CMB temperature. Separately, the deliberately rounded rest input 1420 MHz gives observed frequencies 284, 142, 71 MHz at z = 4, 9, 19 by division by 1+z; the atomic rest frequency is not declared exactly 1420 MHz. No spin-coupling, heating, velocity or ionization history, measured global signal, current detection or upper limit is inferred.Neutral gas can absorb, have zero contrast or emitSeparate prescribed uniform slabs; T_R = 40 K, τ = 0.02, z = 9.T_s is spin temperature, not kinetic temperature by definition.ΔT_obs = (T_s − T_R) [1 − exp(−τ)] / (1 + z).Observed brightness difference · mK · signed linear scale-80-4004080100020406080Supplied spin temperature T_s · kelvinT_s (K)ΔT_obs (mK)Sign10-59.403980Absorption400.000000Zero8079.205307EmissionAt T_s = T_R, nonzero opacity can still give zero contrast.Fixed τ with different T_s can require different columns/profiles.These are separate slabs, not one unchanged column being heated.Rounded ν_0 = 1420 MHz: z = 4, 9, 19 → 284, 142, 71 MHz.No observed global signal, detection or inferred gas history.
The spin temperature specifies the hyperfine level-population ratio n_1/n_0 = 3 exp(−T_*/T_s), with T_* = hν_0/k_B, rather than equalling the gas kinetic temperature by definition. This Rayleigh–Jeans uniform-excitation example uses positive T_s well above T_*. Three separate prescribed slabs share chosen rest-frame background brightness T_R = 40 K, optical depth 0.02 and redshift z = 9. Their spin temperatures are 10, 40, 80 K. Uniform transfer gives T_out (rest) = T_s[1−exp(−τ)] + T_R exp(−τ). After subtracting the unattenuated background and redshifting brightness temperature, ΔT_obs = (T_s−T_R)[1−exp(−τ)]/(1+z). The graph has a linear spin-temperature abscissa in kelvin and a signed linear observed-contrast ordinate in millikelvin, with an explicit zero baseline. Discrete bars, not a time trajectory, give approximately −59.403980, 0, +79.205307 mK; circle endpoints mark absorption/emission and a diamond marks exact zero. Rest-frame outgoing brightnesses are 39.405960, 40, 40.792053 K. At T_s = T_R, emission replaces attenuation and the line contrast vanishes despite nonzero optical depth and neutral gas. Fixed τ across different T_s denotes separate prescribed slabs that may need different columns or line profiles; no one fixed-column cloud is followed as it heats. The 40 K background is supplied, not an observed CMB temperature. Separately, the deliberately rounded rest input 1420 MHz gives observed frequencies 284, 142, 71 MHz at z = 4, 9, 19 by division by 1+z; the atomic rest frequency is not declared exactly 1420 MHz. No spin-coupling, heating, velocity or ionization history, measured global signal, current detection or upper limit is inferred. Original Ark teaching model.
04

A rest-frame transition is observed at a lower frequency

The observed frequency is ν_obs = ν_0/(1 + z). For transparent teaching arithmetic, supply the rounded nominal rest frequency ν_0 = 1420 MHz. This is not a claim that the atomic rest frequency is exactly that rounded number.

With that input, redshifts z = 4, 9 and 19 correspond to frequencies 284, 142 and 71 MHz. The frequency relation labels the propagation redshift; it does not by itself determine spin temperature or neutral abundance.

A real spectral observation also involves instrumental response, foreground radiation and the relation between frequency and the gas sampled along the sightline. Velocity gradients and spatial structure can enter the line-opacity account.

The three brightness rows use a single supplied redshift and separate slab conditions. They are not a measured global spectrum or a predicted signal as a function of frequency across an inferred cosmic history.

05

Contrast is sensitive to more than the presence of neutral atoms

The sign in this example is controlled by T_s − T_R, while the magnitude also depends on optical depth and redshift. Neutral gas alone is therefore insufficient to specify a positive signal or a fixed brightness amplitude.

In a physical history, neutral density, hyperfine coupling, thermal evolution, velocity structure and ionization morphology can all affect the radiation reaching the observer. Their spatial variation carries information beyond one uniform slab.

Zero contrast does not uniquely mean no neutral gas: the T_s = T_R row supplies an explicit alternative. Inferring gas properties requires a model that distinguishes these possibilities and incorporates the observation uncertainties.

This calculation introduces transfer and sign conventions without adopting any present detection, upper limit or measured cosmic-temperature claim. Keep those inference outcomes separate from the recomputable behavior of the supplied slabs.

Worked reasoning

Find the zero-contrast condition

Can the supplied neutral slab with τ = 0.02 have zero line contrast?

  1. Use ΔT_obs = (T_s − T_R)(1 − exp(−τ))/(1 + z).
  2. Set T_s = T_R = 40 K, so the first factor vanishes while τ remains 0.02.
  3. The slab emission replaces the attenuated background exactly in this uniform-source brightness account.

Yes. Its line contrast is zero when T_s equals the background brightness temperature, despite nonzero optical depth.

Try the reasoning

  1. Does neutral hydrogen always produce positive 21-centimetre contrast?

    Show the answer and reasoning

    No.

    The supplied 10 K spin-temperature slab absorbs against its 40 K background, while the 80 K slab gives positive contrast.

  2. Is spin temperature equal to gas kinetic temperature by definition?

    Show the answer and reasoning

    No.

    Spin temperature specifies hyperfine populations; the relevant coupling processes must establish any equality.

  3. What frequency follows at z = 19 from the deliberately rounded 1420 MHz input?

    Show the answer and reasoning

    71 MHz.

    Divide the supplied rest frequency by 1 + z = 20, retaining its rounded teaching-input status.

What to carry forward

  • Spin temperature describes hyperfine populations and needs its own coupling account.
  • Line contrast depends on spin temperature relative to the background and can have either sign or vanish.
  • A supplied slab calculation is distinct from a measured or inferred cosmological 21-centimetre history.

References

Sources supporting the explanations, physical distinctions and examples in this lesson.

  1. Cosmology at Low Frequencies: The 21 cm Transition and the High-Redshift UniverseSteven R. Furlanetto; S. Peng Oh; Frank H. BriggsTeaching resourcearxiv.orgRead source