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Engineering & Technology · Engineering Design Methods & Trade-offs

Cost, manufacturability, maintainability and design constraints

One carrier is assembled from cut panels and screws; another is moulded as one part. The moulded version has fewer assembly steps, but its tooling costs more. Which is cheaper depends partly on how many are needed, and which is useful also depends on repair, cleaning, lead time and the available manufacturing process.

Use the opening design, measurement, sketching and everyday-materials ideas as support. This chapter introduces its own comparison tools and explains the simple weighted sums and cost equations when needed. All users, observations, test results, prices, dimensions and energy values are constructed teaching cases. None is a product specification, legal compliance assessment, real study or population capability limit.

Back to the chapter

After reading, you can

Include production and support consequences in design constraints instead of comparing purchase price alone.

01

Name which limits apply and when

Cost is a resource claim, not one number. Separate development and tooling, material and processing, assembly, inspection, transport, use, maintenance and end-of-life handling. Some costs occur once; others recur per unit or per year. Specify the quantity and time basis before comparing. A low unit price can conceal an unaffordable initial commitment.

Manufacturability concerns making the design reliably with a particular process and capability. Geometry that is easy to sketch may be difficult to form, reach with a cutting tool, assemble or inspect. Material supply, achievable variation, surface quality and rejection rates matter. A process change can alter the geometry and properties, so production planning and design should inform each other.

02

Design the repair task as carefully as the use task

Maintainability concerns inspection, servicing and restoration. Ask which part is likely to wear, how it can be reached, which tool is required, and what must be disconnected or removed first. A replaceable handle is useful only if a suitable replacement exists and removal does not destroy the surrounding carrier.

A screw joint can permit disassembly but add parts and assembly effort; a permanent joint can reduce assembly steps but frustrate a later repair. Neither is universally better. Consider loosening, contamination, inspection and the actual repair setting. Fewer components may simplify one task while forcing replacement of a larger assembly when one small feature fails.

Constraints interact. A thicker wall may improve a test result but increase mass and material use. A tighter fit may reduce movement but demand a more capable process. Keep a visible margin between a limit and the current prediction when possible, and show uncertainty in the prediction. A nominal value at the limit leaves no automatic allowance for variation.

03

Use a simple model within its stated range

For this constructed production comparison, total quoted cost C equals fixed setup cost F plus quantity n multiplied by variable cost v: C = F + nv. Panel assembly A has F = 100 currency units and v = 8 per carrier. Moulding B has F = 700 and v = 3. These assumptions exclude tax, shipping, rejects, future maintenance and changes in capacity.

The graph shows why a process cannot be called cheaper without a quantity. It also makes the model’s limits explicit: straight lines assume the same unit cost at every displayed quantity and no extra batch setup. Real quotations may have steps, minimum orders and uncertain yields.

Fixed and variable costs give a quantity crossoverConstructed total costs intersect at one hundred twenty carriers. The low-setup option is cheaper for smaller quantities under the stated model.Total cost (currency units)004040080800120120016016002002000Quantity n (carriers)A: 100 + 8nB: 700 + 3n
A=100+8n and B=700+3n, currency units. At n=50: 500 and 850. At n=120: both1060. At n=200:1700 and1300. Blue solid A, orange dashed B; model excludes other lifecycle costs.

Find a production crossover, then qualify it

At 50 carriers, A costs 100 + 50 × 8 = 500 units; B costs 700 + 50 × 3 = 850. At 200 carriers, A costs 1700 and B 1300. Setting the totals equal gives 100 + 8n = 700 + 3n, so 5n = 600 and n = 120 carriers. Both totals are then 1060.

Above 120, B is cheaper within these quoted assumptions. That result says nothing by itself about whether its tooling arrives in time, whether its material meets the need or whether its handle can be repaired. A design decision must retain the non-cost constraints and the excluded cost categories.

Try the reasoning

  1. Why might a low per-unit price still exceed a project’s available funds?

    Show the answer and reasoning

    A large fixed setup or tooling payment may be required before any units are produced. Total commitments and timing matter.

  2. Does fewer parts necessarily mean better maintainability?

    Show the answer and reasoning

    No. A one-piece assembly may require replacing the whole item when a small feature fails. Access, replacement availability and repair consequences matter.

  3. At 120 carriers, does the cost model select a process?

    Show the answer and reasoning

    No. Its stated totals tie. Other constraints, uncertainty and excluded lifecycle costs still need evaluation.

What to carry forward

Compare costs on the same basis and examine how a design will be made, inspected and restored.

References

Teaching resources and research supporting this lesson’s explanations and examples.

  1. NASA2 sources
    1. Systems Engineering Handbook — 4.4 Design Solution DefinitionNASAReference guidenasa.govRead source
    2. Systems Engineering Handbook — 6.8 Decision AnalysisNASAReference guidenasa.govRead source
  2. Human factors — DesignHealth and Safety Executive (HSE)Reference guidehse.gov.ukRead source