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Mathematics · Article

Populations, samples and selection bias

Define whose properties a study is meant to describe, then trace how units reach its records. Compare sampling designs, weights, nonresponse and coverage using exact finite examples. Separate chance variation from systematic selection, and distinguish population sampling from causal assignment and generalization.

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After reading, you can

  • Specify a target population, observation and sampling units, reference period and estimand before interpreting a sample.
  • Distinguish a target population, sampling frame, selected sample and responding or otherwise observed units.
  • Define simple random sampling by its possible subsets and explain why equal individual inclusion probabilities are insufficient.
  • Compare stratified, cluster and multistage designs through their actual selection probabilities and precision.
  • Explain inverse inclusion weights and derive design unbiasedness of a finite-population total under stated positive probabilities.
  • Separate a realized sampling error, design bias, variance, standard error and mean-squared error.
  • Recognize the limits of larger samples and weighting when coverage or response mechanisms leave information missing.
  • Distinguish random selection, random treatment assignment, descriptive coverage and transport of effects to a target population.
01

Say whose property is being estimated

A population is the collection of units about which a question is posed. It need not be all people in a country, and it need not be a collection of people at all. The target might be all occupied dwellings in a city on a stated date, all parts produced during a specified shift, or all river reaches in a named drainage area during a season. Unit, eligibility, place and reference time determine membership. A sample can be large and carefully measured while answering a different population question from the one a reader intended.

An estimand is the target quantity defined by that question. For a finite target population U={1,…,N}, with fixed numerical values y₁,…,y_N, a total is T=Σᵢ∈U yᵢ and a mean is μ=T/N when N>0. If yᵢ is an indicator equal to 1 for a defined property and 0 otherwise, μ is a population proportion. A count of events divided by total exposure defines a different estimand from an unweighted average of unit-specific rates. State the numerator, denominator, units and reference period together.

Sampling units, analysis units and reporting units can differ. A survey may first select schools, analyze students within selected schools and obtain some information from parents. A parent who reports for two children is not thereby two independently selected parents. Likewise, a factory inspection might select containers but report properties of items. A sampling description must explain the link between stages and between the units selected and the units whose outcomes enter the estimand.

This lesson uses proportions and elementary algebra for the core examples. Later sections introduce optional finite expectation, design variance and causal connections explicitly, without assuming calculus or the preceding differential-equation branch. Values in a finite population are treated as fixed for the design-based calculations: the repeated variation comes from the declared sampling mechanism. Other probability models can also be useful, but their assumptions must be stated rather than inferred from a spreadsheet.

02

A list used for selection is not automatically the target population

A sampling frame is the operational information from which units can be selected or located. It may be a registry, address list, map of areas or a sequence of production times. The frame and the target are conceptually different. New dwellings can be absent from an old address list; closed businesses can remain on a registry; a person can appear through several accounts. An apparently complete file can therefore have undercoverage, overcoverage or multiplicity even before any sample is drawn.

To connect a frame to a target, specify how frame entries correspond to eligible analysis units. If one person can be reached through two independently selectable phone records, that person may have a different inclusion probability from someone with one record. Counting records as people can change both the population size and the weights. Duplicate removal or multiplicity adjustments need reliable identity and linkage rules; silently assuming every row is one distinct target unit does not solve the problem.

The selected sample consists of the units chosen by the design. The observed or responding set consists of units for which the required usable information is obtained. These sets need not coincide. Some selected units may be ineligible, unreachable, unwilling to participate, or missing only a particular item. A final analysis can impose further eligibility or completeness rules. Each stage should be visible because exclusion can be associated with the outcome even when the original selection was random.

For a simple picture, imagine a target of 100 eligible units, a frame containing 80 of them, a random selection of 40 frame units and 30 completed observations. The numbers 100, 80, 40 and 30 answer different questions. The fraction 30/40 concerns response among selected units under an appropriate denominator; it is not the fraction of the whole target that had a chance to enter the frame. This schematic does not assume equal probabilities or identify a correction from the four counts alone.

Keep the target, frame, selection and response separateThe nested counts are target 100, covered 80, selected 40, and responding 30. Bars share a zero and target-count scale. Response among selected is 3/4. A frame census need not be a complete target census.Keep the target, frame, selection and response separateDefined unit counts; common scale from zero to target counttarget100covered target80selected eligible40usable response30Coverage 4/5; response among selected 3/4.Uncovered target units: 20; frame census: no.
Each proportion names its denominator. The stage counts alone do not identify an outcome mean or establish population representativeness.
Trace membership and observation separately
StageQuestion to documentWhat a count alone cannot establish
Target populationWhich units and reference period define the estimand?Whether an operational list includes them
FrameHow are eligible units represented and linked to entries?Equal inclusion or absence of duplicates
Selected sampleWhich random or other mechanism chooses units?Complete or outcome-independent response
Observed setWhich selected units supplied the required usable items?Unbiased population or causal inference
03

Specify the mechanism, not just a claim of randomness

A sampling design assigns probabilities to possible selected samples. For a target unit i, the first-order inclusion probability πᵢ is the probability that i appears at least once in the selected sample under that design. In the finite without-replacement examples below, each selected unit appears once. For two units i and j, πᵢⱼ is the probability that both are selected; πᵢᵢ=πᵢ. A probability sample uses a known random selection mechanism with positive inclusion probabilities for the target units to which design-based inference is intended to apply.

A statement such as ‘we asked whoever was available’ does not supply those design probabilities. Volunteering, an open website poll, approaching convenient passers-by and selecting conspicuous cases may produce useful observations, but they require separate assumptions to support a population estimate. Calling a procedure random because the analyst did not consciously choose each person does not determine a probability distribution over possible samples. Software randomization also cannot add absent target units to a deficient frame.

For simple random sampling without replacement of a fixed size n from N distinct frame units, every one of the binomial(N,n) subsets has probability 1/binomial(N,n), provided 0≤n≤N. For 0<n≤N, each unit then has πᵢ=n/N. The subset definition is stronger than equal individual probabilities: it specifies how units occur together. Designs with equal πᵢ can have very different joint inclusion probabilities, possible sample compositions and uncertainty.

Neither an unusual realized sample nor apparent demographic balance establishes design bias by itself. Random sampling can occasionally produce an unbalanced sample; a convenient sample can look balanced on a few measured features. The design concerns the probabilities of all possible outcomes of selection. The realized composition is evidence to investigate and report, while a claim about bias needs a target, estimator and mechanism or model. Avoid replacing that analysis with the appearance of one dataset.

04

Equal inclusion probabilities can hide different possible samples

Consider four labeled units with outcomes y₁=y₂=0 and y₃=y₄=10. Select two units. Under simple random sampling, the six subsets {1,2}, {1,3}, {1,4}, {2,3}, {2,4} and {3,4} each have probability 1/6. Each unit occurs in three subsets, so its inclusion probability is 3/6=1/2. The corresponding sample means are 0, 5, 5, 5, 5 and 10. Enumerating the subsets makes both the equal inclusion and the variation visible.

Now group the units into clusters {1,2} and {3,4}, choose either cluster with probability 1/2 and observe both its units. Each individual still has inclusion probability 1/2, but only two of the six size-two subsets are possible. The sample mean is 0 or 10 with equal probabilities. This is a valid probability design for this finite target, but it is not simple random sampling of two individual units. Its all-or-nothing cluster composition follows from the selection rule.

The target mean is 5. The expected sample mean is also 5 under both designs: under SRS it is (0+5+5+5+5+10)/6, and under the cluster design it is (0+10)/2. Thus the cluster mean is design-unbiased despite every realized cluster sample containing only low or only high outcomes. The more extreme possible estimates are a precision issue here. They do not establish systematic overestimation or underestimation across the declared random selections.

The joint probabilities explain what the marginals miss. Under SRS, any two distinct units are selected together with probability 1/6. Under the cluster design, a same-cluster pair has probability 1/2 and a cross-cluster pair has probability 0. These probabilities determine covariation of inclusion indicators. When designing uncertainty calculations, preserve the actual group structure rather than treating all observed rows as independently selected individuals.

Possible samples belong to a declared designsimple random sampling without replacement. Four fixed outcomes are 0, 0, 10, 10. Each listed sample has its exact declared probability and exact mean. All unit inclusion probabilities are 1/2, 1/2, 1/2, 1/2. This is enumeration, not random animation or an observed sampling history.Possible samples belong to a declared designFixed population: unit identifier above its outcomeunit 10unit 20unit 310unit 410Possible sampleprobabilitymean{1, 2}1/60{1, 3}1/65{1, 4}1/65{2, 3}1/65{2, 4}1/65{3, 4}1/610Target mean 5; design mean expectation 5.The exact list and probabilities, rather than row count alone, determine the design.
Equal marginal inclusion probabilities can coexist with different possible samples and estimator precision.
Three size-two designs for the same four labeled units
DesignPossible sample means and their probabilitiesIndividual inclusion
SRS of two units0 with 1/6; 5 with 4/6; 10 with 1/6πᵢ=1/2 for every unit
One whole homogeneous cluster0 with 1/2;10 with 1/2πᵢ=1/2 for every unit
One unit per homogeneous stratum5 with probability 1πᵢ=1/2 for every unit
05

Use the structure of selection when comparing designs

Stratification divides the frame into nonoverlapping groups and samples within each group according to a declared design. A stratum might be a geographic region, production line or other auxiliary category known before observing the study outcome. In the four-unit example, use {1,2} as one stratum and {3,4} as the other, then select one unit uniformly from each, independently across strata. Every possible sample contains one value 0 and one value 10, so its mean is exactly 5. The lack of variation depends on these constant within-stratum outcomes.

Cluster sampling instead selects groups and observes all or a sample of their members. It can reduce travel or administrative effort because selected units are nearby or share a sampling list. When group members resemble each other in the outcome of interest, observing more members of one group can provide less new information than observing similarly many units spread over groups. That is an explanation to examine for a given outcome and design, not a universal theorem that clustering must always be worse.

Multistage designs can combine these ideas: select areas, then households within selected areas, then a person within selected households. Probabilities at later stages are conditional on the earlier selections. The final inclusion probability follows the actual selection pathways and their conditional probabilities. If a unit can be reached by more than one pathway, simply multiplying one path’s probabilities can miss the other ways of inclusion. The worked product later in the lesson explicitly assumes one nested route.

Systematic selection uses a random start and a fixed interval on an ordered frame under a specified rule. It is not automatically the same as simple random sampling: ordering and periodic patterns can affect which groups of units appear together. Likewise, sampling with replacement produces draw probabilities and possible repeated observations that must be distinguished from probabilities of inclusion at least once. Choose the estimator and uncertainty calculation for the actual design rather than transfer a familiar formula solely because the sample size is the same.

Within-group and between-group selection differThe population groups are units 1,2 with outcome 0 and units 3,4 with outcome 10. The selected finite design is one uniform unit per stratum, independently across strata. All allowed samples are shown as connected selected identifiers. A line denotes set membership, not physical distance. The design mean variance is 0 squared outcome units.Within-group and between-group selection differFixed groups; layout is schematic, not geographical distance1: 02: 03: 104: 10Allowed identifier pairs and exact probabilities{1, 3}p = 1/4{1, 4}p = 1/4{2, 3}p = 1/4{2, 4}p = 1/4Selected design: one per homogeneous stratum.No universal claim that every stratification or cluster design has this precision.
Selecting one unit per homogeneous stratum and selecting one whole homogeneous cluster use the same group boundaries in different ways.
06

Inverse inclusion weights estimate a total under explicit conditions

If unit i has known πᵢ>0 and contributes its value yᵢ when selected, its design weight is wᵢ=1/πᵢ. The Horvitz–Thompson total is T̂_HT=Σᵢ∈s yᵢ/πᵢ, where s is the selected set. A unit selected with probability 1/10 contributes ten times its observed value to this total. The interpretation is expansion under the design; it does not assert that the observed unit is literally identical to ten particular unseen units. A weight is tied to a sampling mechanism and an estimand.

The proof of unbiasedness is finite algebra. Define Iᵢ=1 if unit i is included and 0 otherwise, so E_d(Iᵢ)=πᵢ, where E_d means the probability-weighted average across possible samples under the design. Write T̂_HT=Σᵢ∈U Iᵢyᵢ/πᵢ. By linearity, E_d(T̂_HT)=Σᵢ∈U yᵢ E_d(Iᵢ)/πᵢ=Σᵢ∈U yᵢ=T. No independence of the Iᵢ is used. The proof does require the correct positive inclusion probabilities and the stipulated availability of each selected value.

When the population size N is known, μ̂_HT=T̂_HT/N is design-unbiased for μ=T/N. A different estimator is the ratio μ̂_R=(Σᵢ∈s wᵢyᵢ)/(Σᵢ∈s wᵢ) for a nonempty sample with positive weights. Its denominator is a sample-dependent estimate of population size unless the design or calibration makes it fixed. The expectation of a ratio is not generally the ratio of expectations. Normalizing weights can be useful, but it changes the estimator and its finite-sample properties.

Weighting cannot be justified merely by selecting numbers that make a desired result appear. Document design weights, any response adjustments, calibration constraints and changes such as trimming separately. A survey inclusion probability, a conditional response probability and a treatment propensity describe different mechanisms. They can enter a carefully derived estimator together, but they are not interchangeable labels for the same inverse weight. If values are missing after selection, the pure design proof alone no longer establishes the claimed observed-data estimator.

Expansion weights follow the actual inclusion probabilitiesPopulation values are 2, 4, 8 and one-draw inclusion probabilities 1/2, 1/3, 1/6. Each card separates the value, probability, inverse weight and whole-target HT total. Whole-target HT is available. Supported-target contributions are not relabelled as estimates of the whole target.Expansion weights follow the actual inclusion probabilitiesunit 1y = 2pi = 1/21/pi = 2HT = 4unit 2y = 4pi = 1/31/pi = 3HT = 12unit 3y = 8pi = 1/61/pi = 6HT = 48Whole target total 14; HT expectation 14.A zero-inclusion unit cannot be recovered by increasing another unit’s weight.
HT unbiasedness concerns a probability-weighted design expectation. The inverse weight is not a claim that an observed unit equals particular unseen units.
07

A three-unit example separates three estimators

Take the fixed population values 2, 4 and 8, with total 14 and mean 14/3. Select exactly one unit, with probabilities 1/2, 1/3 and 1/6 respectively. These probabilities sum to 1 and are also the units’ first-order inclusion probabilities because there is only one draw. The three possible Horvitz–Thompson totals are 2/(1/2)=4, 4/(1/3)=12 and 8/(1/6)=48. Their probability-weighted average is (1/2)4+(1/3)12+(1/6)48=14.

A naive expansion by N=3 instead gives totals 6, 12 or 24. Its expected value is (1/2)6+(1/3)12+(1/6)24=11, so its design bias for the total is 11−14=−3. The low value 2 is more likely to be selected than the high value 8. Treating the draw as if all three units had probability 1/3 ignores exactly the feature that makes the ordinary expansion wrong for this design.

For the known-size HT mean, divide the correct total estimator by 3; its expectation is 14/3. For the ratio-weighted mean based on this one observation, the weight cancels: (yᵢ/πᵢ)/(1/πᵢ)=yᵢ. Its expectation is (1/2)2+(1/3)4+(1/6)8=11/3, with bias 11/3−14/3=−1. Therefore positive, correct weights in a ratio do not guarantee exact finite-sample unbiasedness. The numerator’s unbiasedness and the denominator’s unbiasedness do not prove it either.

The correct HT total can still be variable. Its squared deviations from 14 are 100, 4 and 1156, so Var_d(T̂_HT)=(1/2)100+(1/3)4+(1/6)1156=244. The units of this variance are squared outcome-total units; the standard deviation is √244=2√61 in total units. Unbiasedness concerns the center over repeated selections, not closeness of every possible estimate or superiority in mean-squared error. This deliberately small example makes those distinctions visible without asymptotic approximations.

Unbiasedness and probability-weighted squared error differFor target mean 14/3, the known-N HT mean has design expectation 14/3, bias 0 and squared error average 244/9. The normalized ratio mean has expectation 11/3, bias -1 and squared error average 50/9. Here squared error average means sum of sample probability times estimate-minus-target squared; the formal MSE definition follows in the next manuscript section.Unbiasedness and probability-weighted squared error differSquared error average = sum p(sample) × (estimate − target)².One possible draw123probability1/21/31/6HT known-N mean4/3416normalized ratio mean248HT: E 14/3; bias 0; squared error 244/9Ratio: E 11/3; bias -1; squared error 50/9Target 14/3; mean units for bias and squared mean units for squared error.All outcomes/probabilities are hypothetical givens; no repeated-draw simulation is used.
The probability-weighted squared error is defined here before the later formal MSE discussion. A variable unbiased estimator can have greater squared error average than a biased alternative in this particular finite problem.
One draw with unequal probabilities
Selected outcome and probabilityHT total yᵢ/πᵢNaive total 3 yᵢRatio mean
2; probability 1/2462
4; probability 1/312124
8; probability 1/648248
Design expectation141111/3
08

Distinguish an error from a property of the estimator

For an estimator θ̂ of a fixed target θ, a realized error is θ̂−θ. Its design bias is E_d(θ̂)−θ, and its design variance is Var_d(θ̂)=E_d[(θ̂−E_dθ̂)²]. The design standard error is √Var_d(θ̂); in practice it often must itself be estimated. When these finite expectations exist, MSE_d(θ̂)=E_d[(θ̂−θ)²]=Var_d(θ̂)+Bias_d(θ̂)². This identity follows by expanding θ̂−θ=(θ̂−E_dθ̂)+(E_dθ̂−θ) and noting that the first term has mean zero.

For the four-unit population, the SRS mean has variance (25+0+0+0+0+25)/6=25/3. The cluster mean has variance (25+25)/2=25. The one-per-stratum mean has variance 0 in this special constant-within-stratum case. All have expectation 5. The cluster-to-SRS variance ratio, called a design effect for this estimator, outcome and comparison, is 25/(25/3)=3. This is not a design effect for every possible variable measured on those units.

The same SRS variance can be written (1−n/N)S²/n, where S²=Σᵢ∈U(yᵢ−μ)²/(N−1), N>1, and 1≤n≤N for this without-replacement mean. Here S²=100/3, N=4 and n=2, giving (1−1/2)(100/3)/2=25/3. The finite-population correction reflects the specified sampling without replacement. The population spread S², variance of an estimator and squared standard error play different roles. This formula should not be applied to clustered, nonresponding or convenient observations just by substituting their row count.

An advanced distinction concerns which uncertainty can be estimated from an observed sample. For a fully specified finite population, Var_d(T̂_HT)=ΣᵢΣⱼ(πᵢⱼ−πᵢπⱼ)yᵢyⱼ/(πᵢπⱼ). This follows from Cov_d(Iᵢ,Iⱼ)=πᵢⱼ−πᵢπⱼ. The usual unbiased sample-based pair formula divides relevant terms by πᵢⱼ and therefore needs positive pair probabilities for those terms. In the one-draw example all πᵢ>0 but πᵢⱼ=0 for distinct units. The total remains unbiased and its theoretical variance is defined, but the ordinary pairwise unbiased variance estimator cannot be formed for the unobserved pairs. Extra structure or conservative alternatives require their own argument.

Marginal positivity and pair positivity are differentThe four-by-four matrix contains exact joint inclusion probabilities, including pi_ii=pi_i. Diagonal probabilities are 1/2, 1/2, 1/2, 1/2. Every distinct pair is positive: no. Theoretical HT total variance is 400 squared total units and agrees with finite enumeration. Zero cells are explicitly marked, not assigned a small positive probability.Marginal positivity and pair positivity are differentExact joint probabilities; rows and columns are unit identifiers112233441/21/2001/21/200001/21/2001/21/2All pi_i > 0:yesAll distinct pairs > 0:noMean variance 25; SRS benchmark 25/3.The benchmark is an SRS formula, not a replacement for the selected design.
The complete hypothetical population determines a theoretical variance even when an unrestricted sample-based pairwise variance formula lacks positive pair support.
09

Equal sample counts need not represent equal population counts

Suppose a population has two known strata: 80 units in A, each with outcome 10, and 20 units in B, each with outcome 50. Select 10 units by SRS within each stratum and obtain every selected outcome. The population total is 80·10+20·50=1800, and its mean is 18. The ordinary mean of the 20 observed rows is (10·10+10·50)/20=30 because the smaller stratum contributes half the sample instead of one fifth of the population.

The stratum inclusion probabilities are 10/80=1/8 and 10/20=1/2, so the design weights are 8 and 2. The weighted total is 10·8·10+10·2·50=1800. The sum of weights is 10·8+10·2=100, the known population size. Here dividing the weighted total by N or by the sum of weights gives the same mean 18. The denominator is fixed by this particular fixed-allocation stratified design, unlike the random denominator of the earlier one-draw ratio example.

The weighted estimate is exact in every possible sample here because all outcomes within each stratum are identical. In an ordinary population with variation within strata, the same known-N HT construction is design-unbiased under the stated within-stratum selection, but individual estimates vary. Disproportionate allocation can deliberately improve information about a small stratum; it is not a mistake merely because sample fractions differ. The error is to ignore the allocation when interpreting an estimator for the whole population.

Calibration adjusts weights to satisfy known auxiliary totals or counts. It can align an estimate with the population’s known stratum composition and can sometimes improve precision under suitable designs and relationships. It does not reveal unobserved outcomes by algebra alone. If respondents within a calibration cell differ systematically in the outcome from nonrespondents, reproducing the cell count does not guarantee that its weighted outcome total is correct. The target, auxiliary information, adjustment rule and assumptions must remain visible.

Unequal population shares need explicit expansion weightsThe two strata have population counts 80, 20 and sample counts 10, 10. Their inverse selection weights are 8, 2. The ordinary sample mean is 30 and whole-target weighted mean 18. A zero-selected stratum has no observed mean and no finite design weight.Unequal population shares need explicit expansion weightsPopulation shares (top) and sample shares (bottom)A80 population10 sampledpi 1/8; weight 8; observed mean 10B20 population10 sampledpi 1/2; weight 2; observed mean 50Row mean 30; whole-target mean estimate 18.A missing target stratum cannot be filled by merely calibrating another stratum.
Known stratum counts and the declared within-stratum selection supply these weights. Exact recovery here additionally uses stipulated constant within-stratum outcomes.
10

Response is an additional selection process

Unit nonresponse occurs when a selected eligible unit does not provide the required survey information; item nonresponse concerns a particular missing variable. Both can change the observed set. If people with longer working hours are less likely to respond to a survey about working hours, an initially sound probability sample can yield an unrepresentative respondent mean. The concern is a relationship between the observation process and the target quantity, not simply the existence of missing records.

Consider a target of 100 units in two known auxiliary cells A and B of size 50 each. In this hypothetical population, every A unit has binary outcome 1 and every B unit has outcome 0. Invite everyone. All 50 A units respond, while exactly 10 B respondents are chosen uniformly within B. The response rate is 60/100=3/5; the respondent outcome proportion is 50/60=5/6; the target proportion is 50/100=1/2. Under this fixed-count response design, every possible respondent set has the same mean, so its bias is 5/6−1/2=1/3.

The known auxiliary cells must be available beyond the respondents; they are not labels reconstructed from the missing outcomes. In the specified example, response probabilities are 1 in A and 1/5 in B. Weights 1 and 5 produce weighted outcome total 50 and weighted count 100, recovering proportion 1/2. Exact recovery depends on the constant outcomes within cells and the stated response mechanism. For variable outcomes, a response adjustment needs appropriate assumptions about the relation between response and outcomes within the available cells.

A response rate alone cannot identify the size or direction of nonresponse bias. A low rate could occur under an outcome-independent mechanism, while a higher rate could still exclude a scientifically distinctive group. Report response definitions, follow-up procedures, observed differences and sensitivity to plausible missing-data assumptions. Neither imputing a value nor increasing a respondent’s weight makes an assumption disappear. Missingness mechanisms and their identification receive fuller treatment in later statistics; here the central task is to show where selection enters.

Response is another selection mechanismKnown cells have sizes 50, 50 and response counts 50, 10. Within-cell response probabilities are 1, 1/5. Inverse response weights are 1, 5. The respondent mean is 5/6 and whole-target adjusted proportion 1/2 under the stipulated mechanism.Response is another selection mechanismBlue: known cell size. Orange: fixed responding countA5050response p 1; inverse weight 1B5010response p 1/5; inverse weight 5Response fraction 3/5; respondent proportion 5/6.Conditional whole-target adjustment 1/2; target truth 1/2.
Known auxiliary cells and response assumptions are additional information. A response rate alone does not establish bias or validate the adjustment.
Separate response percentages from target outcome proportions
QuantityValue in the declared two-cell exampleInterpretation
Response rate60/100=3/5Usable responses among the 100 invited target units
Respondent outcome proportion50/60=5/6Outcome among observed respondents
Target outcome proportion50/100=1/2Outcome among all target units
Adjusted proportion under the stated cell assumptions50/(50+5·10)=1/2A justified result for this mechanism, not a rate-only correction
11

Some target information cannot be obtained from the same frame

Suppose 20 of 100 target units never occur in the sampling frame. Each has inclusion probability 0 under every sample restricted to that frame. If the remaining 80 units all have outcome 0, even observing all of them leaves open what the excluded units would have reported. A larger sample drawn from the same covered group gives more complete information about that group, but it does not create observations from the absent one.

Compare two possible fixed target populations. In world A, all 20 uncovered units also have outcome 0, so the target mean is 0. In world B, all 20 uncovered units have outcome 1, so the target mean is 20/100=1/5. The frame, selection mechanism and every covered outcome are identical in the two worlds. Consequently, no analysis using only those covered data can distinguish these target means without additional information or assumptions. This is an identification limitation, not merely a large sampling standard error.

The HT proof required πᵢ>0. There is no finite design weight 1/πᵢ when πᵢ=0, and multiplying observed outcomes by larger finite weights does not recover an unknown excluded-group outcome. A new frame, supplementary data, a narrower declared target or an explicit extrapolation model might address the problem. Each changes the information or question. Reporting a small variance for the covered-group estimate does not establish that its value is the desired whole-target mean.

For bounded binary outcomes in this particular example, the covered data do give a useful bound: the unknown total lies between 0 and 20, and the target mean lies in [0,1/5]. The two constructed worlds attain the endpoints. Such partial information should not be replaced by a single unjustified point estimate. Bounds, sensitivity analyses and scientific knowledge can clarify what is and is not learned, provided their assumptions and target remain explicit.

Undercoverage can leave a logical range, not a pointKnown covered positives are 0 out of 80 covered target units. There are 20 uncovered units. The whole-target binary proportion lies in the exact closed interval [0, 1/5]. Filled endpoints are attainable hypothetical completions, not imputed outcomes or a confidence level.Undercoverage can leave a logical range, not a pointKnown positives 0; uncovered units 20Possible target proportion; common zero-to-one scale00.250.50.751Lower bound 0; upper bound 1/5Point identified: no; interval width 1/5The missing outcomes remain unspecified; both extremes respect the given range.This interval has no assigned confidence level and is not a point imputation.
Coverage information plus a binary outcome range gives sharp logical identification bounds. More observations from the same incomplete frame need not collapse this range.
12

More records address some uncertainty but not every source of error

Increasing a well-designed sample can reduce sampling variation, but ‘more observations’ is not a universal cure for selection. In the zero-coverage example, a census of the 80 frame units still leaves the 20 target outcomes unidentified. Repeatedly adding records from an open volunteer mechanism can make the respondent distribution very stable while preserving a difference from the target. The distinction is between precision for an observed mechanism and validity for the intended population quantity.

Under SRS without replacement from the correctly defined finite target, observing all N units makes the sampling variance of its descriptive mean zero. That claim concerns the declared values and the sampling stage. Measurements can still have error, records can be duplicated or mislinked, questions can be interpreted differently, and the chosen definition can fail to capture the intended construct. A nominal census therefore does not establish perfect data quality, and a census of a frame is not automatically a census of the target.

Selection bias is a systematic discrepancy tied to how units enter an analysis and how the chosen estimator relates to its target under a specified mechanism or model. Coverage and nonresponse are common routes. Measurement error, processing error and sampling variation are distinct concepts even though they can interact. It is useful to trace them separately because a design weight aimed at unequal selection does not automatically repair a miscalibrated instrument or a changed outcome definition.

When comparing procedures, define the loss and constraints. An unbiased estimator may have large variance; a deliberately stabilized or modeled estimator may introduce bias while lowering mean-squared error under stated assumptions. Cost, precision, robustness and coverage can all matter. The finite MSE identity describes a mathematical tradeoff, but it does not authorize concealing bias or choosing an estimator after seeing a preferred result. Preserve the design and report sensitivity to assumptions that cannot be checked from observed outcomes alone.

13

Multiply the right conditional probabilities

Take a unit contained in a single nested cluster. Let C mean that the cluster is selected, S mean that the unit is selected within it, and R mean that the unit supplies the needed response. Suppose P(C)=1/4, P(S|C)=2/5 and P(R|S,C)=4/5. Because selection of the unit requires its cluster, the unit inclusion probability is P(S∩C)=P(C)P(S|C)=1/10. Its design weight for the selected-unit total is 10.

The probability of an observed response through this route is P(C∩S∩R)=P(C)P(S|C)P(R|S,C)=(1/4)(2/5)(4/5)=2/25. If these probabilities are truly known for that unit and the relevant outcomes are observed whenever R occurs, an inverse observed-probability construction uses 25/2. The multiplication is the conditional-probability chain rule. It does not assume that cluster inclusion, unit selection and response are independent events with those marginal probabilities.

In practice response probabilities are often unknown and estimated from available covariates. An estimated response model adds identification, estimation and specification assumptions. The chain-rule arithmetic cannot establish that the model contains the variables needed to make response conditionally unrelated to the outcome. Likewise, multiple routes to selection, unequal cluster sizes or within-household rules must be included in the actual probability calculation. A single illustrative product is not a universal weighting formula for every complex survey.

Keep design and response stages in the record so an analyst can reproduce the reasoning. A selected unit may have a valid design weight even when one outcome is missing. Complete-case analysis then introduces outcome-specific observation probabilities. Different variables can therefore use different observed sets despite originating in the same survey. Documenting these mechanisms is essential for comparisons across outcomes, years and linked datasets; a common filename or a shared sample-size label does not make the estimands identical.

Multiply conditional stages along the stated unique routeThe three conditional factors are 1/4, 2/5, 4/5. Their first two factors give selection probability 1/10; all three give observation probability 2/25. Selection inverse weight 10 differs from combined observed-data weight 25/2. The chain rule does not require independent stages.Multiply conditional stages along the stated unique routecluster selected1/4unit | cluster2/5response | selected4/5Selection probability: 1/10Observed probability: 2/25Selection weight 10; combined weight 25/2The response factor describes a different mechanism from the sampling design.Zero response has no finite observed-data expansion weight.
The unique nested route is an explicit condition. Multiple routes of inclusion need a separate path/union calculation.
14

Population description and causal effects ask different questions

Random selection determines who enters a study from a population or frame. Random assignment determines which treatment, intervention or exposure level the study units receive under an experimental design. One can occur without the other. A probability sample observed without an intervention can support a descriptive population estimate under its design. A randomized experiment among volunteers can support an internally valid treatment comparison under appropriate conditions, while its target-population scope requires a separate argument.

For the causal connection, let Yᵢ(1) and Yᵢ(0) denote the outcome unit i would have under two specified exposure levels. Their difference is an individual causal contrast, and a population average contrast is N⁻¹Σᵢ[Yᵢ(1)−Yᵢ(0)]. Only the outcome under the received exposure is normally observed. These potential outcomes are a mathematical way to define a question; specifying them in a thought experiment does not mean they can be recovered from an ordinary census.

Imagine observing all 100 units in a finite target. Fifty have Yᵢ(0)=Yᵢ(1)=1 and fifty have Yᵢ(0)=Yᵢ(1)=0. Expose 40 of the first group and 10 of the second. Among 50 exposed units the observed mean is 40/50=4/5; among 50 unexposed units it is 10/50=1/5. Their difference is 3/5. Yet every individual causal contrast is 0, so the true population average effect in this stipulated world is 0. Perfect descriptive coverage did not remove confounding in exposure assignment.

Observational causal identification is possible under suitable designs and assumptions; it is not ruled out simply because assignment was not randomized. A common sufficient setup requires a well-defined intervention and consistency linking observed and potential outcomes, conditional exchangeability of exposure given adequate pre-exposure covariates, and positive probability of each relevant exposure within those covariate groups. Assumptions about interference and the assignment structure also matter. The point here is to distinguish those causal requirements from survey inclusion probabilities, not to infer a causal effect from a sample weight alone.

A complete census does not make exposure contrasts causalBoth potential outcomes are supplied only as a thought experiment, in Y(0),Y(1) order. High-type outcomes 1, 1 and low-type outcomes 0, 0 define stipulated population effect 0. Actual assigned groups have observed means 4/5 and 1/5, with contrast 3/5. Empty groups stay unassigned. Equal fixed counts do not establish random assignment.A complete census does not make exposure contrasts causalStipulated types; Y(0),Y(1) are hypothetical, not jointly observedexposed countunexposedhigh: 50 unitsY(0),Y(1): 1, 14010low: 50 unitsY(0),Y(1): 0, 01040Observed means: exposed 4/5, unexposed 1/5Observed contrast 3/5; stipulated causal effect 0.Balanced counts or complete coverage do not establish exchangeable assignment.
The unobserved counterfactual outcome is hypothetical input, not recovered census information. Selection for description and exposure assignment for causal inference remain separate.
Two separate dimensions of a study
QuestionA relevant mechanismA limit that remains
Who represents the target?Frame coverage and population sampling or participationTreatment assignment may still be confounded
What causes an outcome difference?Random assignment or an explicit causal identification strategyThe study population may differ from the intended target
Are observations measured correctly?Outcome definitions, instruments and data processingRandom selection or assignment alone cannot certify measurement
15

Randomization does not automatically transport an effect

An effect can vary across groups. Suppose a target is 20% group A and 80% group B. In a hypothetical world, the average treatment effect is 4 in A and 1 in B, measured in the same outcome units under the same intervention definition. The target average effect is 0.2·4+0.8·1=8/5. A perfectly randomized trial containing only A units can identify an A-specific contrast under the trial’s causal conditions, but its population contrast is 4 in this example rather than 8/5.

The group-B effect 1 is stipulated for this thought experiment, not estimated from the A-only trial. If a different world had another B effect but exactly the same A outcomes and trial records, the trial alone would not distinguish the target effects. Weighting the observed A participants cannot create observed B treatment comparisons. This is a support problem for participation in the target, even if both treatment arms are present within A.

When the required target groups are represented, transport or generalization can sometimes use covariates, target distributions and explicit assumptions about how causal effects or potential outcomes relate across participation groups. A suitable overlap condition, compatible measurement and intervention definitions, internal causal validity, and justified cross-population assumptions are required. The exact sufficient conditions depend on the scientific question and strategy. Treatment positivity within a trial and participation positivity across target groups concern different mechanisms.

These connections also arise when taking a factory experiment from one production line to another, transferring an education intervention across schools, or applying an ecological result across habitats. The units, outcomes, effect modifiers and target conditions must be considered scientifically. An abstract about trial generalizability supports the distinction in scope; the arithmetic above is an original finite thought experiment. It is not a claim that one universal reweighting recipe settles transport or a recommendation about any real intervention.

Trial support and target applicability are separate conditionsTrial shares are 1, 0 and target shares 1/5, 4/5 for groups A,B. Effects 4, 1 are hypothetical givens. All positive target groups have trial support: no. Stipulated trial effect 4 and target effect 8/5 differ by composition; absent-group effects are not estimated by weighting another group.Trial support and target applicability are separate conditionsBlue: group A. Orange: group B. Each bar totals onetrial1 ; 0target1/5 ; 4/5Unsupported target share: 4/5Conditional supported formula: unassignedHypothetical effects: A 4, B 1; target 8/5.Group effects and target applicability are not identified by the weights alone.
Even a supported reweighting expression is conditional on the stipulated group effects and their applicability. Randomization alone does not automatically transport an effect.
16

Make the route from target to conclusion inspectable

A clear sampling account begins with the target population and estimand, then describes the frame, sampling units, stages, eligibility rules, selected counts and usable-response counts. State whether selection was with or without replacement and how randomization was implemented. Report available inclusion probabilities or weights and the procedure used to estimate uncertainty. For a multistage survey, preserve the strata and cluster information needed for the design rather than stripping it away because the final file contains individual rows.

Explain changes between design weights and final analysis weights. If nonresponse adjustment, calibration, trimming or imputation is used, name the auxiliary information, constraints and assumptions. Report the analysis denominator for each outcome and account for missing items and exclusions. These details allow another reader to distinguish a justified population estimate from a respondent summary. A polished chart and a large row count cannot substitute for the selection history.

Match the conclusion to the evidence. A sample mean describes the observed values. A design-based population estimate additionally uses a declared probability design and appropriate estimator. A model-based extrapolation additionally uses its model assumptions. A causal contrast additionally needs an identification strategy, and transfer to another population needs its own scope argument. Each step can be legitimate, but each adds conditions. State uncertainties and limitations at the step where they enter rather than attaching a vague caveat after a broad claim.

The practical habit is to ask four connected questions: Who is the target? How could each unit enter the data? What quantity does this estimator compute under that mechanism? What assumptions connect it to the intended conclusion? The finite examples make the answers checkable: equal inclusion need not mean SRS; an extreme sample need not prove bias; correct ratio weights need not give exact unbiasedness; a census need not identify a causal effect. Carry these distinctions into later probability, estimation, regression and experimental-design lessons.

Trace the estimand through the actual mechanism

These controls enumerate small hypothetical problems. Every design probability, target value, fraction, variance and squared-error average is exact. Optional standard-error decimals are explicitly Approx. There is no simulated survey or random sampling animation.

Define the target and the probability-weighted errors

The expectation averages an estimator over its declared possible samples with their probabilities. Bias is that expectation minus the stated target. Variance averages squared deviations from the expectation. The squared-error average, also called MSE, instead averages squared deviations from the target and equals variance plus squared bias. Means, totals and their squared units are kept distinct; none is a guarantee about every sample.

Support, response and causal conditions remain separate

Zero target inclusion or zero response in a positive target cell prevents an unrestricted whole-target expansion. Supported contributions are labelled for their smaller target. Coverage bounds are logical ranges, not confidence intervals. Both potential outcomes and group causal effects are supplied only as hypothetical truths. Complete counts, balanced exposure or trial weights establish neither causal identification nor general transport.

1. Follow target units through observation

Keep the target, frame, selection and response separateThe nested counts are target 100, covered 80, selected 40, and responding 30. Bars share a zero and target-count scale. Response among selected is 3/4. A frame census need not be a complete target census.Keep the target, frame, selection and response separateDefined unit counts; common scale from zero to target counttarget100covered target80selected eligible40usable response30Coverage 4/5; response among selected 3/4.Uncovered target units: 20; frame census: no.
Each proportion names its denominator. The stage counts alone do not identify an outcome mean or establish population representativeness.
Nested unit counts and explicitly named denominators
Quantity and target conditionsExact selected result or labelled Approx
Defined target unit count100
Target units represented by the frame80
Selected eligible units40
Usable responding units30
Target units outside coverage20
Covered target units not selected40
Selected units without usable response10
Covered / target4/5
Selected / covered target1/2
Usable response / selected eligible3/4
Usable response / target3/10
All covered target units are selectedno
Target, coverage, selection and response coincideno
An outcome quantity is identified from these counts aloneno

Units: Defined units and dimensionless fractions, with each denominator named.

The counts are nested target/covered/selected/responding stages of a stipulated study. A census of the frame can retain target undercoverage. An empty selected set has no response fraction. Counts alone supply neither outcomes, independence, representativeness nor a particular estimand value.

2. Compare exact finite sampling designs

Possible samples belong to a declared designsimple random sampling without replacement. Four fixed outcomes are 0, 0, 10, 10. Each listed sample has its exact declared probability and exact mean. All unit inclusion probabilities are 1/2, 1/2, 1/2, 1/2. This is enumeration, not random animation or an observed sampling history.Possible samples belong to a declared designFixed population: unit identifier above its outcomeunit 10unit 20unit 310unit 410Possible sampleprobabilitymean{1, 2}1/60{1, 3}1/65{1, 4}1/65{2, 3}1/65{2, 4}1/65{3, 4}1/610Target mean 5; design mean expectation 5.The exact list and probabilities, rather than row count alone, determine the design.
Equal marginal inclusion probabilities can coexist with different possible samples and estimator precision.
Marginal positivity and pair positivity are differentThe four-by-four matrix contains exact joint inclusion probabilities, including pi_ii=pi_i. Diagonal probabilities are 1/2, 1/2, 1/2, 1/2. Every distinct pair is positive: yes. Theoretical HT total variance is 400/3 squared total units and agrees with finite enumeration. Zero cells are explicitly marked, not assigned a small positive probability.Marginal positivity and pair positivity are differentExact joint probabilities; rows and columns are unit identifiers112233441/21/61/61/61/61/21/61/61/61/61/21/61/61/61/61/2All pi_i > 0:yesAll distinct pairs > 0:yesMean variance 25/3; SRS benchmark 25/3.The benchmark is an SRS formula, not a replacement for the selected design.
The complete hypothetical population determines a theoretical variance even when an unrestricted sample-based pairwise variance formula lacks positive pair support.
Possible samples, first/joint inclusion and complete theoretical moments
Quantity and target conditionsExact selected result or labelled Approx
Declared finite designsimple random sampling without replacement
Fixed hypothetical population values and identifiers[{ id: 1; outcome: 0 }; { id: 2; outcome: 0 }; { id: 3; outcome: 10 }; { id: 4; outcome: 10 }]
Known population size N4
Fixed sample size n2
Every possible sample: identifiers, probability, values and estimators[{ unit indices: [0; 1]; unit ids: [1; 2]; probability: 1/6; outcomes: [0; 0]; sample mean: 0; ht total: 0; ht known n mean: 0; weight sum: 4; normalized ratio mean: 0 }; { unit indices: [0; 2]; unit ids: [1; 3]; probability: 1/6; outcomes: [0; 10]; sample mean: 5; ht total: 20; ht known n mean: 5; weight sum: 4; normalized ratio mean: 5 }; { unit indices: [0; 3]; unit ids: [1; 4]; probability: 1/6; outcomes: [0; 10]; sample mean: 5; ht total: 20; ht known n mean: 5; weight sum: 4; normalized ratio mean: 5 }; { unit indices: [1; 2]; unit ids: [2; 3]; probability: 1/6; outcomes: [0; 10]; sample mean: 5; ht total: 20; ht known n mean: 5; weight sum: 4; normalized ratio mean: 5 }; { unit indices: [1; 3]; unit ids: [2; 4]; probability: 1/6; outcomes: [0; 10]; sample mean: 5; ht total: 20; ht known n mean: 5; weight sum: 4; normalized ratio mean: 5 }; { unit indices: [2; 3]; unit ids: [3; 4]; probability: 1/6; outcomes: [10; 10]; sample mean: 10; ht total: 40; ht known n mean: 10; weight sum: 4; normalized ratio mean: 10 }]
Total possible-sample probability1
First-order unit inclusion probabilities[1/2; 1/2; 1/2; 1/2]
Exact joint-inclusion matrix, including the diagonal[[1/2; 1/6; 1/6; 1/6]; [1/6; 1/2; 1/6; 1/6]; [1/6; 1/6; 1/2; 1/6]; [1/6; 1/6; 1/6; 1/2]]
Covariances of the inclusion indicators[[1/4; -1/12; -1/12; -1/12]; [-1/12; 1/4; -1/12; -1/12]; [-1/12; -1/12; 1/4; -1/12]; [-1/12; -1/12; -1/12; 1/4]]
All target units have positive first-order inclusionyes
All distinct target pairs have positive joint inclusionyes
Fixed hypothetical target total20
Fixed hypothetical target mean5
Sample mean: target, expectation, bias, variance, squared error average and exact SE{ target: 5; expectation: 5; bias: 0; variance: 25/3; mse: 25/3; mse variance bias identity residual: 0; standard error: { coefficient: 5/3; radicand: 3 }; standard error approx: ≈ 2.8867513; unbiased for stated target: yes }
HT total: complete finite-design moments{ target: 20; expectation: 20; bias: 0; variance: 400/3; mse: 400/3; mse variance bias identity residual: 0; standard error: { coefficient: 20/3; radicand: 3 }; standard error approx: ≈ 11.547005; unbiased for stated target: yes }
Known-N HT mean: complete finite-design moments{ target: 5; expectation: 5; bias: 0; variance: 25/3; mse: 25/3; mse variance bias identity residual: 0; standard error: { coefficient: 5/3; radicand: 3 }; standard error approx: ≈ 2.8867513; unbiased for stated target: yes }
Normalized weighted mean: finite-design moments{ target: 5; expectation: 5; bias: 0; variance: 25/3; mse: 25/3; mse variance bias identity residual: 0; standard error: { coefficient: 5/3; radicand: 3 }; standard error approx: ≈ 2.8867513; unbiased for stated target: yes }
Theoretical HT total variance from full joint formula400/3
Joint variance formula minus exact enumeration0
Population spread with denominator N-1100/3
SRS without-replacement finite-population correction1/2
SRS benchmark variance for this outcome and n25/3
The selected design itself is SRSyes
Selected mean variance / SRS benchmark variance1
Unrestricted all-pair variance estimator positivity condition holdsyes
This finite enumeration is a random simulationno

Units: Outcome means/totals in the stated outcome unit; design variance and MSE in its square. Probabilities are dimensionless.

Every listed possible sample and its probability is enumerated exactly; no random path is simulated. The fixed hypothetical population supplies the theoretical target and variance. Equal first-order inclusion does not make the sample designs identical. Zero pair probabilities obstruct the usual unrestricted all-pair variance-estimator condition, while theoretical variance and first-order HT unbiasedness can remain valid. The SRS formula is a labelled benchmark for other designs, not their uncertainty formula.

3. Inverse weights and a normalized ratio

Expansion weights follow the actual inclusion probabilitiesPopulation values are 2, 4, 8 and one-draw inclusion probabilities 1/2, 1/3, 1/6. Each card separates the value, probability, inverse weight and whole-target HT total. Whole-target HT is available. Supported-target contributions are not relabelled as estimates of the whole target.Expansion weights follow the actual inclusion probabilitiesunit 1y = 2pi = 1/21/pi = 2HT = 4unit 2y = 4pi = 1/31/pi = 3HT = 12unit 3y = 8pi = 1/61/pi = 6HT = 48Whole target total 14; HT expectation 14.A zero-inclusion unit cannot be recovered by increasing another unit’s weight.
HT unbiasedness concerns a probability-weighted design expectation. The inverse weight is not a claim that an observed unit equals particular unseen units.
Unbiasedness and probability-weighted squared error differFor target mean 14/3, the known-N HT mean has design expectation 14/3, bias 0 and squared error average 244/9. The normalized ratio mean has expectation 11/3, bias -1 and squared error average 50/9. Here squared error average means sum of sample probability times estimate-minus-target squared; the formal MSE definition follows in the next manuscript section.Unbiasedness and probability-weighted squared error differSquared error average = sum p(sample) × (estimate − target)².One possible draw123probability1/21/31/6HT known-N mean4/3416normalized ratio mean248HT: E 14/3; bias 0; squared error 244/9Ratio: E 11/3; bias -1; squared error 50/9Target 14/3; mean units for bias and squared mean units for squared error.All outcomes/probabilities are hypothetical givens; no repeated-draw simulation is used.
The probability-weighted squared error is defined here before the later formal MSE discussion. A variable unbiased estimator can have greater squared error average than a biased alternative in this particular finite problem.
Whole-target and supported-target estimator distributions
Quantity and target conditionsExact selected result or labelled Approx
Complete hypothetical finite population values[2; 4; 8]
One-draw inclusion probabilities[1/2; 1/3; 1/6]
Probability sum1
Known population size N3
Target total14
Target mean14/3
Inverse inclusion factors where positive[2; 3; 6]
All target units have positive inclusionyes
Joint matrix: distinct pairs cannot appear in one draw[[1/2; 0; 0]; [0; 1/3; 0]; [0; 0; 1/6]]
All distinct pair probabilities are positiveno
Possible naive N-times-value totals[6; 12; 24]
Possible ordinary one-observation means[2; 4; 8]
Whole-target HT totals, only if positivity holds[4; 12; 48]
Known-N HT means, only if positivity holds[4/3; 4; 16]
Normalized-ratio means on possible positive-probability draws[2; 4; 8]
Naive total moments for the whole target{ target: 14; expectation: 11; bias: -3; variance: 41; mse: 50; mse variance bias identity residual: 0; standard error: { coefficient: 1; radicand: 41 }; standard error approx: ≈ 6.4031242; unbiased for stated target: no }
Ordinary mean moments for the whole target{ target: 14/3; expectation: 11/3; bias: -1; variance: 41/9; mse: 50/9; mse variance bias identity residual: 0; standard error: { coefficient: 1/3; radicand: 41 }; standard error approx: ≈ 2.1343747; unbiased for stated target: no }
Whole-target HT total moments{ target: 14; expectation: 14; bias: 0; variance: 244; mse: 244; mse variance bias identity residual: 0; standard error: { coefficient: 2; radicand: 61 }; standard error approx: ≈ 15.620499; unbiased for stated target: yes }
Known-N HT mean moments{ target: 14/3; expectation: 14/3; bias: 0; variance: 244/9; mse: 244/9; mse variance bias identity residual: 0; standard error: { coefficient: 2/3; radicand: 61 }; standard error approx: ≈ 5.2068331; unbiased for stated target: yes }
Normalized-ratio mean moments{ target: 14/3; expectation: 11/3; bias: -1; variance: 41/9; mse: 50/9; mse variance bias identity residual: 0; standard error: { coefficient: 1/3; radicand: 41 }; standard error approx: ≈ 2.1343747; unbiased for stated target: no }
Separately labelled supported-contribution expansions[4; 12; 48]
Total over positive-inclusion units only14
Supported-contribution moments for that smaller target{ target: 14; expectation: 14; bias: 0; variance: 244; mse: 244; mse variance bias identity residual: 0; standard error: { coefficient: 2; radicand: 61 }; standard error approx: ≈ 15.620499; unbiased for stated target: yes }
Whole-target HT estimator is availableyes
Probability-weighted squared-error convention and pacingProbability-weighted squared errors over this exact one-draw design; formal MSE definition appears next in the manuscript.

Units: Stated outcome units for estimator values; squared outcome units for variance/MSE. Inclusion and draw probabilities coincide only for this one draw.

A one-observation normalized inverse-weight ratio cancels to the observed value. That does not make it unbiased under unequal draw probabilities. A zero-inclusion target unit leaves the whole-target HT estimator unassigned; supported contributions are separately labelled for their smaller supported target. Zero-probability outcomes are not simulated observations. The theoretical values use the stipulated complete finite population, not information recovered from one observed sample.

4. Population composition and sample allocation

Unequal population shares need explicit expansion weightsThe two strata have population counts 80, 20 and sample counts 10, 10. Their inverse selection weights are 8, 2. The ordinary sample mean is 30 and whole-target weighted mean 18. A zero-selected stratum has no observed mean and no finite design weight.Unequal population shares need explicit expansion weightsPopulation shares (top) and sample shares (bottom)A80 population10 sampledpi 1/8; weight 8; observed mean 10B20 population10 sampledpi 1/2; weight 2; observed mean 50Row mean 30; whole-target mean estimate 18.A missing target stratum cannot be filled by merely calibrating another stratum.
Known stratum counts and the declared within-stratum selection supply these weights. Exact recovery here additionally uses stipulated constant within-stratum outcomes.
Observed stratum information and conditional expansion
Quantity and target conditionsExact selected result or labelled Approx
Stipulated within-stratum selection/responseSRS without replacement, complete response
Known target population size100
Total observed sample size20
Population/sample counts, shares, inclusion factors, weights and observed stratum means[{ id: A; population count: 80; sample count: 10; constant outcome: 10; population share: 4/5; sample share: 1/2; inclusion: 1/8; design weight: 8; observed stratum mean: 10; expanded count: 80 }; { id: B; population count: 20; sample count: 10; constant outcome: 50; population share: 1/5; sample share: 1/2; inclusion: 1/2; design weight: 2; observed stratum mean: 50; expanded count: 20 }]
Complete hypothetical target total1800
Complete hypothetical target mean18
Ordinary observed-row mean30
Ordinary mean minus target in this constant-outcome example12
Every target stratum has positive selectionyes
Whole-target HT total when supported1800
Whole-target known-N mean when supported18
Whole-target normalized weighted mean when supported18
Sum of observed design weights100
Weighted count minus known N0
Expanded total of supported strata only1800
Normalized mean of the supported population only18
Whole-target HT variance under stipulated constant stratum outcomes0
An unsupported stratum outcome is learned from weights aloneno

Units: Outcome unit for means/totals; population/sample counts and dimensionless shares. Variance has squared outcome units.

Within-stratum SRS and complete response are stipulated. Constant outcomes make every supported stratum sample exact in this hypothetical population. A zero-selected target stratum has no observed mean or finite design weight; no whole-target estimate is assigned from the other stratum. The complete hypothetical target truth remains distinct from the supported observed-data calculation. Calibration of counts alone does not reveal unknown outcomes.

5. Preserve the response mechanism

Response is another selection mechanismKnown cells have sizes 50, 50 and response counts 50, 10. Within-cell response probabilities are 1, 1/5. Inverse response weights are 1, 5. The respondent mean is 5/6 and whole-target adjusted proportion 1/2 under the stipulated mechanism.Response is another selection mechanismBlue: known cell size. Orange: fixed responding countA5050response p 1; inverse weight 1B5010response p 1/5; inverse weight 5Response fraction 3/5; respondent proportion 5/6.Conditional whole-target adjustment 1/2; target truth 1/2.
Known auxiliary cells and response assumptions are additional information. A response rate alone does not establish bias or validate the adjustment.
Known auxiliary cells and explicit response support
Quantity and target conditionsExact selected result or labelled Approx
Stipulated fixed-count response designFixed counts; uniform responding subset within each known auxiliary cell
Known auxiliary-cell population count100
Total responding count60
Cell counts, outcomes, response probabilities and inverse weights[{ id: A; population count: 50; constant binary outcome: 1; response count: 50; response probability: 1; inverse response weight: 1; observed cell mean: 1 }; { id: B; population count: 50; constant binary outcome: 0; response count: 10; response probability: 1/5; inverse response weight: 5; observed cell mean: 0 }]
Responding / target invited units3/5
Exact respondent positive-outcome total50
Respondent outcome proportion5/6
Complete hypothetical target proportion1/2
Respondent proportion minus target1/3
Every positive target cell has responsesyes
Sum of supported observed inverse-response weights100
Supported-cell adjusted outcome total only50
Whole-target adjusted total when support holds50
Whole-target adjusted proportion when support holds1/2
Normalized supported-cell proportion1/2
Supported whole-target adjustment minus stipulated target0
Adjusted variance under the stipulated constant cell outcomes0
The response mechanism is learned from the rate aloneno

Units: Binary proportions and response probabilities are dimensionless; adjusted totals count positive outcomes.

Known auxiliary cell counts, fixed-count uniform response within each cell, and constant within-cell outcomes are stipulated. They make the displayed supported adjustment exact here. Zero response in a target cell leaves no finite inverse-response weight and no whole-target adjusted proportion. A response rate alone establishes neither this mechanism nor the size/direction of bias in an arbitrary population.

6. Bound what the frame cannot reveal

Undercoverage can leave a logical range, not a pointKnown covered positives are 0 out of 80 covered target units. There are 20 uncovered units. The whole-target binary proportion lies in the exact closed interval [0, 1/5]. Filled endpoints are attainable hypothetical completions, not imputed outcomes or a confidence level.Undercoverage can leave a logical range, not a pointKnown positives 0; uncovered units 20Possible target proportion; common zero-to-one scale00.250.50.751Lower bound 0; upper bound 1/5Point identified: no; interval width 1/5The missing outcomes remain unspecified; both extremes respect the given range.This interval has no assigned confidence level and is not a point imputation.
Coverage information plus a binary outcome range gives sharp logical identification bounds. More observations from the same incomplete frame need not collapse this range.
Sharp logical target bounds without point imputation
Quantity and target conditionsExact selected result or labelled Approx
Target unit count100
Covered target count80
Uncovered target count20
Known positive outcomes among covered units0
Declared binary outcome range[0; 1]
Covered fraction of target4/5
Known covered-set positive proportion0
Possible uncovered positive counts, lower/upper[0; 20]
Sharp logical lower bound for target proportion0
Sharp logical upper bound for target proportion1/5
Lower completion is attainableyes
Upper completion is attainableyes
Logical identification interval width1/5
Target proportion is point identified by the stipulated informationno
Whole-target point value when the interval collapsesUnassigned for the stated target/domain/support conditions.
Uncovered values have been imputedno
A sampling confidence level is assignedno

Units: Unit counts and dimensionless binary proportions.

The binary outcome range and known covered outcomes imply sharp logical bounds, not a sampling confidence interval or assumed distribution of uncovered outcomes. Both endpoints can be attained by stipulated uncovered values, but no particular completion is selected or imputed. A complete target census collapses the interval; a frame census alone need not.

7. Multiply the right conditional stages

Multiply conditional stages along the stated unique routeThe three conditional factors are 1/4, 2/5, 4/5. Their first two factors give selection probability 1/10; all three give observation probability 2/25. Selection inverse weight 10 differs from combined observed-data weight 25/2. The chain rule does not require independent stages.Multiply conditional stages along the stated unique routecluster selected1/4unit | cluster2/5response | selected4/5Selection probability: 1/10Observed probability: 2/25Selection weight 10; combined weight 25/2The response factor describes a different mechanism from the sampling design.Zero response has no finite observed-data expansion weight.
The unique nested route is an explicit condition. Multiple routes of inclusion need a separate path/union calculation.
Selection and observed-data probabilities under one route
Quantity and target conditionsExact selected result or labelled Approx
Explicit inclusion-route assumptionone unique nested route
Cluster selection probability1/4
Unit selection conditional on selected cluster2/5
Response conditional on selection4/5
Final selection inclusion probability1/10
Final observed-data probability2/25
Inverse selection probability10
Inverse conditional response factor5/4
Combined observed-data inverse factor25/2
Product of inverse factors minus combined factor0
Independent stages are required for this conditional chain ruleno
Multiple alternative inclusion routes are automatically handledno

Units: Dimensionless conditional probabilities and inverse-probability factors.

Products use the stated conditional probabilities along one unique nested route; they do not assume independent stages. An observed probability adds the response condition to selection. Zero conditional response leaves no finite observed-data expansion weight even if selection remains positive. Multiple inclusion routes require their own union/path calculation, not automatic multiplication of one route.

8. A descriptive census and a causal contrast

A complete census does not make exposure contrasts causalBoth potential outcomes are supplied only as a thought experiment, in Y(0),Y(1) order. High-type outcomes 1, 1 and low-type outcomes 0, 0 define stipulated population effect 0. Actual assigned groups have observed means 4/5 and 1/5, with contrast 3/5. Empty groups stay unassigned. Equal fixed counts do not establish random assignment.A complete census does not make exposure contrasts causalStipulated types; Y(0),Y(1) are hypothetical, not jointly observedexposed countunexposedhigh: 50 unitsY(0),Y(1): 1, 14010low: 50 unitsY(0),Y(1): 0, 01040Observed means: exposed 4/5, unexposed 1/5Observed contrast 3/5; stipulated causal effect 0.Balanced counts or complete coverage do not establish exchangeable assignment.
The unobserved counterfactual outcome is hypothetical input, not recovered census information. Selection for description and exposure assignment for causal inference remain separate.
Observed group outcomes versus stipulated causal truth
Quantity and target conditionsExact selected result or labelled Approx
Hypothetical potential-outcome scopeStipulated thought experiment; both potential outcomes are not observed in an actual census
Potential-outcome array order[Y(0),Y(1)]
Complete descriptive target size100
High-type units in the stipulated population50
Low-type units50
Hypothetical high-type Y(0),Y(1)[1; 1]
Hypothetical low-type Y(0),Y(1)[0; 0]
Exposed high-type count40
Exposed low-type count10
Unexposed high-type count10
Unexposed low-type count40
Total exposed count50
Total unexposed count50
Outcome total observed under exposure40
Outcome total observed without exposure10
Observed exposed-group mean when nonempty4/5
Observed unexposed-group mean when nonempty1/5
Descriptive exposed-minus-unexposed mean contrast3/5
Stipulated high-type causal contrast0
Stipulated low-type causal contrast0
Complete hypothetical population causal effect0
Observed descriptive contrast minus stipulated causal effect3/5
Every target unit is descriptively observedyes
Random exposure assignment is established by countsno
Both potential outcomes are recovered from the censusno

Units: The stipulated outcome unit for observed means and causal contrasts.

Both potential outcomes are supplied only as a thought-experiment truth. The census observes the outcome under each received exposure, not both potential outcomes. A descriptive group contrast can differ from the stipulated causal effect despite complete population coverage. Empty groups have no observed mean/contrast, and balanced exposure counts alone do not prove random assignment or exchangeability.

9. Trial support and an explicit target

Trial support and target applicability are separate conditionsTrial shares are 1, 0 and target shares 1/5, 4/5 for groups A,B. Effects 4, 1 are hypothetical givens. All positive target groups have trial support: no. Stipulated trial effect 4 and target effect 8/5 differ by composition; absent-group effects are not estimated by weighting another group.Trial support and target applicability are separate conditionsBlue: group A. Orange: group B. Each bar totals onetrial1 ; 0target1/5 ; 4/5Unsupported target share: 4/5Conditional supported formula: unassignedHypothetical effects: A 4, B 1; target 8/5.Group effects and target applicability are not identified by the weights alone.
Even a supported reweighting expression is conditional on the stipulated group effects and their applicability. Randomization alone does not automatically transport an effect.
Supported reweighting under hypothetical group-effect applicability
Quantity and target conditionsExact selected result or labelled Approx
Stipulated group-effect/applicability scopeKnown hypothetical effects, not estimates from absent B observations; randomization alone does not transport
Target population shares of A,B[1/5; 4/5]
Trial shares of A,B[1; 0]
Target shares sum1
Trial shares sum1
Hypothetical group effects, not absent-group estimates[4; 1]
Target mixture effect under those givens8/5
Trial mixture effect under those givens4
Trial mixture minus target mixture effect12/5
Support condition in each positive target group[yes; no]
Every positive target group has trial supportno
Target/trial share ratios where their denominator is positive[1/5; Unassigned for the stated target/domain/support conditions.]
Target share without trial support4/5
Supported reweighting formula under stipulated applicabilityUnassigned for the stated target/domain/support conditions.
Conditional formula minus hypothetical target effectUnassigned for the stated target/domain/support conditions.
A missing trial-group effect is observed from the trialno
Target applicability of group effects is stipulatedyes
Weights alone establish general causal transportno

Units: Dimensionless group shares/weights; effects retain the stated outcome unit.

The group effects and their applicability are hypothetical givens, not estimates inferred from absent trial-group observations. Every positive target group needs trial support for this reweighting calculation. A zero target-and-trial share needs no target contribution and gets no artificial 0/0 weight. The supported formula is conditional on the stipulated group-effect applicability; randomization or weights alone establish no general transport claim.

Worked examples

Label each stage before calculating a fraction

A city study targets 100 eligible households on a stated date. Its frame lists 80 of them. It selects 40 frame households and obtains 30 usable responses. The analysis concerns individual children, whose information is reported by a parent. Identify the population, stages and units, and interpret the response fraction.

  1. The stated target is the 100 eligible households for the household-selection stage. If the desired estimand concerns children, the target children and their eligibility must also be defined; household membership links them to the selected households. A household is not interchangeable with a child or a reporting parent.
  2. The frame contains 80 target households and omits 20. The 40 selected households form the selected sample, and the 30 usable responding households form the observed household set. These stages are distinct even if all numbers come from one project.
  3. Under the stipulated eligibility and usable-response denominator, the household response fraction is 30/40=3/4. The fraction of target households represented on the frame is 80/100=4/5. Neither fraction is an outcome proportion among children.
  4. The counts do not specify individual child inclusion probabilities. Household sizes, selection within households, response and the child-level estimand must be documented before constructing child weights or an uncertainty estimate.

The household response fraction is 3/4, frame coverage is 4/5, and household, child and reporter are different units; the counts alone do not establish child-level representativeness.

Check whether equal inclusion really means SRS

Four labeled units have values 0, 0, 10, 10. Compare SRS of two units with selecting either pair {1, 2} or {3, 4}, each with probability 1/2. Find the inclusion probabilities, sample-mean distributions and expectations.

  1. Under SRS the six subsets are {1,2}, {1,3}, {1,4}, {2,3}, {2,4}, {3,4}, each with probability 1/6. Every unit belongs to three subsets, so every inclusion probability is 1/2. The sample means are 0, 5, 5, 5, 5, 10.
  2. Under the pair-selection design, each unit belongs to exactly one of the two possible selected pairs. Its inclusion probability is again 1/2, but the only possible means are 0 and 10, each with probability 1/2.
  3. The SRS expectation is (0+5+5+5+5+10)/6=5. The pair-design expectation is (0+10)/2=5, the true target mean. Both estimators are unbiased under their own declared design.
  4. SRS requires equal probabilities for every size-two subset, not merely equal unit probabilities. The cluster design excludes four subsets and has different pairwise inclusion. Its extreme realized means reflect variability, not design bias in this example.

Both designs have πᵢ=1/2 and an unbiased mean 5, but only the six-subset design is SRS.

Construct and average an inverse-probability total

Select exactly one of three units with outcomes 2, 4, 8 and probabilities 1/2, 1/3, 1/6. Compute the HT total in each case and its design expectation, then compare naive multiplication by 3.

  1. The true total is 2+4+8=14. Each probability is positive and the three sum to 1. The possible weights are 2, 3, 6.
  2. Multiply the selected outcome by its own inverse probability. The HT totals are 2·2=4, 4·3=12 and 8·6=48.
  3. Average the estimates with the selection probabilities, not with equal weights across the three cases: E_d(T̂_HT)=(1/2)4+(1/3)12+(1/6)48=2+4+8=14.
  4. The naive totals 3 yᵢ are 6, 12, 24. Their expectation is 3+4+4=11, giving bias −3 for the target total 14. Expanding by 3 would be appropriate for an equal one-of-three draw, which is a different design.

The HT totals 4, 12, 48 average to 14 under the design; naive totals 6, 12, 24 average to 11 and are biased downward by 3.

Do not exchange a ratio and its expectation

Use the previous unequal one-draw design. Compare T̂_HT/3 with the normalized weighted mean (Σwᵢyᵢ)/(Σwᵢ). Explain why the latter can be biased despite using the correct weights.

  1. The population size is the known constant N=3. Therefore E_d(T̂_HT/3)=E_d(T̂_HT)/3=14/3, the target mean.
  2. There is only one selected observation. Its normalized weighted mean is (wᵢyᵢ)/wᵢ=yᵢ, so its possible values are 2, 4, 8 with the original probabilities 1/2, 1/3, 1/6.
  3. The expected ratio is 1+4/3+4/3=11/3. Subtracting the target 14/3 gives bias −1.
  4. The weighted count Σwᵢ has possible values 2, 3, 6 and expectation 3, but its randomness matters. E(A/B) need not equal E(A)/E(B). This counterexample does not claim that ratio estimators are always poor; it rejects an incorrect blanket proof of finite-sample unbiasedness.

The known-N HT mean is unbiased for 14/3; the one-observation ratio mean has expectation 11/3 and bias −1.

Compare precision without relabeling variability as bias

For the population 0, 0, 10, 10 and sample size 2, compute the variance of the SRS mean, whole-cluster mean and one-per-homogeneous-stratum mean. Give the cluster design effect relative to SRS.

  1. All three expectations are the target mean 5. For SRS, squared deviations of the six equiprobable sample means are 25, 0, 0, 0, 0, 25, so variance is 50/6=25/3.
  2. For whole-cluster selection, the means 0 and 10 each have squared deviation 25 and probability 1/2. The variance is 25.
  3. One uniform selection from each homogeneous stratum always yields one 0 and one 10. Every sample mean is 5, so its variance is 0. Constant within-stratum outcomes make this special result exact.
  4. The cluster-to-SRS variance ratio is 25/(25/3)=3. The corresponding design standard errors are 5/√3, 5 and 0 in outcome units. This comparison is tied to these fixed values, sample size and estimators; it does not establish a universal ranking for all variables or costs.

The variances are 25/3, 25 and 0 respectively; the cluster design effect is 3 for this outcome and comparison.

Represent a small stratum without confusing its population share

A has 80 units all at outcome 10; B has 20 units all at 50. SRS selects 10 from each stratum with full response. Compare the raw sample mean with a design-weighted mean and total.

  1. The true population total is 80·10+20·50=1800 and its mean is 1800/100=18. Equal sample counts do not imply equal population counts.
  2. The observed unweighted mean is (10·10+10·50)/20=30. It gives each stratum half of the numerical influence although B contains only one fifth of the population.
  3. The inclusion probabilities are 1/8 and 1/2, so the weights are 8 and 2. The weighted total is 10·8·10+10·2·50=800+1000=1800.
  4. The weighted count is 10·8+10·2=100, so the weighted mean is 18. Exactness in every sample uses constant outcomes within each stratum. With variable outcomes the known-N weighted estimator is unbiased under the stated design, not necessarily exactly equal to the population mean in one sample.

The raw mean is 30; the justified weighted total is 1800 and weighted mean 18 with weights 8 and 2.

Trace a correction to its known auxiliary information

A target of 100 has two known auxiliary cells of 50 units each. Every A outcome is 1 and every B outcome is 0. All A units and a uniformly selected fixed set of 10 B units respond. Compute the response rate, respondent proportion, bias and a cell-adjusted proportion.

  1. The number of respondents is 50+10=60, so the response rate is 3/5. There are 50 positive outcomes among respondents, giving proportion 5/6.
  2. The target has 50 positive outcomes among 100 units, giving proportion 1/2. Since the within-cell outcomes and response counts are fixed, every allowed respondent set gives 5/6; the naive respondent proportion therefore has response-design bias 1/3.
  3. The cell response probabilities are 1 and 10/50=1/5. Their inverse weights are 1 and 5. Weighted outcome total is 50·1·1+10·5·0=50 and weighted count is 50+50=100, giving 1/2.
  4. The cells are known auxiliary groups available for all invited units. The calculation does not pretend that missing outcomes are observed in order to form adjustment cells. Recovery depends on the stipulated cell structure and response mechanism; matching cell counts alone cannot repair arbitrary within-cell outcome selection.

Response rate 3/5 and respondent proportion 5/6 are different; the naive bias is 1/3, while the stated cell adjustment recovers 1/2.

Show what an uncovered group leaves unidentified

Eighty covered target units all have binary outcome 0; twenty target units have no chance of selection from the frame. Compare worlds in which those twenty outcomes are all 0 or all 1. What does a census of the covered frame establish?

  1. A census of the 80 covered units establishes covered total 0 and covered mean 0. It supplies no outcome measurement for any uncovered unit.
  2. If all 20 uncovered outcomes are 0, the target total is 0 and target mean 0. If all are 1, the target total is 20 and target mean 1/5.
  3. Both worlds produce exactly the same covered observations, even with full frame response. Therefore the whole-target mean is not identified by the covered data alone.
  4. Because outcomes are binary, the target mean is bounded by 0 and 1/5 in this setup. A finite 1/π weight does not exist for π=0. Narrowing the target to the covered 80 answers a different question; extrapolating to the other 20 requires new information or assumptions.

The covered mean is 0, but the whole-target mean can range from 0 to 1/5; more frame-only observations cannot identify it.

Use a conditional product rather than unrelated marginals

A unit has a unique nested selection route. Its cluster is selected with probability 1/4, it is selected within that cluster with conditional probability 2/5, and it responds given those selections with probability 4/5. Find its selection and observed-response probabilities and inverse weights.

  1. Let C denote cluster selection and S unit selection conditional on C. The unit inclusion probability is P(C∩S)=P(C)P(S|C)=(1/4)(2/5)=1/10.
  2. The design weight is 1/(1/10)=10. This weight refers to the selected unit before its response status is added.
  3. With R denoting response, P(C∩S∩R)=P(C)P(S|C)P(R|S,C)=(1/10)(4/5)=2/25. The reciprocal observed probability is 25/2.
  4. The product uses conditional probabilities by the chain rule, not an independence assumption. The last reciprocal is justified only when the actual relevant response probability and observation assumptions are available; estimating a response model adds conditions.

Selection probability 1/10 gives design weight 10; observed-response probability 2/25 gives inverse 25/2 under the declared mechanism.

Separate a descriptive census from a causal contrast

In a fully observed target of 100 units, 50 have Y(0)=Y(1)=1 and 50 have Y(0)=Y(1)=0. Expose 40 high-outcome and 10 low-outcome units. Compare the observed exposure association with the average causal effect in this hypothetical world.

  1. The exposed group has 50 units and 40 observed positive outcomes, so its mean is 4/5. The unexposed group contains the remaining 10 high and 40 low units, giving mean 1/5.
  2. The observed exposed-minus-unexposed difference is 4/5−1/5=3/5. It is a correct descriptive association for this complete observed population.
  3. Every unit has Y(1)−Y(0)=0 by the stipulation. Consequently the population average causal effect is 0. The high-outcome group was more likely to be exposed, creating the observed contrast without an effect.
  4. Potential outcomes are specified here to construct a counterexample, not inferred from the observed census. The example shows why complete coverage does not randomize exposure; it does not rule out observational identification with suitable causal assumptions or other designs.

The census association is 3/5, while the stipulated population average causal effect is 0.

Identify the missing scope assumption

An ideal randomized trial includes only group A, whose average effect is 4. A target population is 20% A and 80% B. In a specified thought experiment the B effect is 1. Compute the trial and target contrasts, then say whether weighting A-only trial participants identifies the latter without that stipulation.

  1. Under the trial’s internal causal conditions, its group-specific contrast is 4. The target contrast under the stipulated two-group world is (1/5)4+(4/5)1=8/5.
  2. The trial contrast exceeds this target contrast by 4−8/5=12/5. Different group composition matters because the group effects differ.
  3. Group B has no trial representation. The given B effect is an assumption of the example, not a value supplied by random assignment among A participants. Reweighting only A observations cannot reveal a missing B effect.
  4. To infer a target contrast from actual data, a strategy needs relevant support and justified cross-population assumptions, together with internal causal validity and compatible definitions. Random treatment assignment and population participation are distinct mechanisms.

The trial contrast is 4 and the stipulated target contrast 8/5; A-only trial weighting does not identify the missing B contribution.

An unbiased estimator need not minimize squared error

Return to the one-draw outcomes 2, 4, 8 with probabilities 1/2, 1/3, 1/6 and target total 14. Compare the MSE of HT totals 4, 12, 48 with that of naive totals 6, 12, 24. Does the comparison justify calling the naive estimator unbiased?

  1. The HT expectation is 14 and its variance is 244, so its MSE is 244. Its three squared errors are 100, 4, 1156 and their probability-weighted average is 244.
  2. The naive estimator has expectation 11 and bias −3. Its errors from the target 14 are −8, −2, 10, so its MSE is (1/2)64+(1/3)4+(1/6)100=32+4/3+50/3=50.
  3. Its variance about its own mean 11 is (1/2)25+(1/3)1+(1/6)169=41. Thus MSE=41+(−3)²=50, consistent with the finite bias-variance identity.
  4. The biased estimator has lower MSE for this particular fixed population and squared-error criterion. It is still biased. The example separates two properties; it does not establish a universally superior estimator or authorize choosing an unreported estimator after inspecting the desired outcome.

HT is unbiased with MSE 244; the naive total is biased by −3 with variance 41 and MSE 50 in this specified example.

Try it yourself

  1. An online survey claims to describe ‘the city’. Give three pieces of population information needed before a numerical conclusion has a clear target.

    Show the answer and reasoning

    For example: the eligible unit type, the geographic boundary and the reference date or period; the target quantity must also be defined.

    Residents, households, registered businesses and website visitors are different populations. A specified proportion or mean needs both population membership and an outcome definition. The phrase alone does not establish that respondents are a probability sample.

  2. A frame contains 400 eligible units. A design selects 100 of them and 70 give usable responses to an item. Is 70/100 a population outcome proportion?

    Show the answer and reasoning

    No. Under the stipulated denominator it is the item’s usable-response fraction, 7/10.

    The numerator counts usable observations rather than units with the outcome of interest. Population description additionally needs the target, coverage, selected-unit probabilities and the response mechanism. The item’s observed set can differ from another item’s.

  3. Under SRS without replacement of 3 units from 8 distinct units, what is the probability of each size-three subset and of including one specified unit?

    Show the answer and reasoning

    Each subset has probability 1/56, and a specified unit has inclusion probability 3/8.

    There are binomial(8,3)=56 subsets. A specified unit occurs with any 2 of the other 7 units, hence in binomial(7,2)=21 subsets, giving 21/56=3/8. Equal subset probabilities, not just equal marginal inclusion, define this SRS design.

  4. A design selects either {1,2} or {3,4}, each with probability 1/2. Is it SRS of two from four because every unit has inclusion probability 1/2?

    Show the answer and reasoning

    No; four of the six size-two subsets have probability 0.

    SRS would give every size-two subset probability 1/6. The declared cluster design is still a probability design, but its joint inclusion structure differs. Equal individual inclusion probabilities do not determine that structure.

  5. A selected unit has measured value 12 kg and known inclusion probability 1/4. What is its contribution to an HT total, and what units does it have?

    Show the answer and reasoning

    Its design weight is 4 and its total contribution is 48 kg.

    The weight is the dimensionless reciprocal of a probability. Multiplying 12 kg by 4 gives 48 kg as an expansion contribution. It does not mean the measured unit itself physically contains 48 kg or identify four particular units with the same value.

  6. In the finite HT unbiasedness proof, must the inclusion indicators of different units be independent?

    Show the answer and reasoning

    No. Correct positive first-order inclusion probabilities and linearity of expectation suffice for the total’s design unbiasedness.

    For each unit E_d(Iᵢyᵢ/πᵢ)=yᵢ. Summing these equalities does not require independence. Joint inclusion probabilities matter for variance, and missing outcomes after selection require a separate observation argument.

  7. Exactly one selected observation has value y and design weight w>0. What is its normalized weighted mean? Does the correct weight alone prove this mean is population-unbiased?

    Show the answer and reasoning

    The ratio is wy/w=y; the correct weight alone does not prove unbiasedness.

    With one observation the weight cancels. Under unequal selection probabilities the selected value can have an expectation different from the unweighted finite-population mean. A random denominator cannot be replaced by its expectation inside a ratio.

  8. An estimator has design expectation 11/3 for a target mean 14/3. Find its design bias. Does a single realized estimate above the target contradict that bias?

    Show the answer and reasoning

    The bias is −1; a realized estimate above the target is compatible with a negative design bias.

    Bias compares the probability-weighted center of all possible estimates with the target. A particular realization can lie on either side. For the one-draw example, the value 8 is above 14/3 even though the ratio mean’s expectation is below it.

  9. An unbiased total estimator has design variance 244 in squared kilograms. What are its MSE and standard error, and can its realized error be nonzero?

    Show the answer and reasoning

    MSE is 244 kg²; the design standard error is √244 kg=2√61 kg; its realized error can be nonzero.

    Unbiasedness sets the average signed error to zero, not every error. The standard error is the square root of estimator variance and has the same units as the total. It is not the variance or the spread of individual population values.

  10. For the same outcome and sample size, an estimator has cluster-design variance 25 and SRS variance 25/3. Find the design effect and state a limit on interpreting it.

    Show the answer and reasoning

    The variance ratio is 3; it applies to that outcome, estimator, sample size and comparison design.

    Compute 25/(25/3)=3. The result does not by itself compare costs, establish bias, or give the design effect of every other outcome. A particular stratum construction can reduce variance without guaranteeing the same reduction for all variables.

  11. A stratum of size 60 is sampled by SRS of 15 with complete response. What is each unit’s inclusion probability and design weight?

    Show the answer and reasoning

    The inclusion probability is 1/4 and the design weight is 4.

    For fixed-size within-stratum SRS, π=n_h/N_h=15/60. The reciprocal expands a selected unit’s contribution for a stratum total. Whole-population estimation must also account for the other strata and the appropriate population denominator.

  12. Two surveys each have response rate 60%. Must they have the same nonresponse bias for a population mean?

    Show the answer and reasoning

    No; the response rate alone does not identify the relation between response and the outcome.

    Bias depends on the target, estimator and mechanism. One survey could respond independently of the outcome under a stated model, while another disproportionately misses a distinctive group. The rate is useful process information but is not itself a bias estimate.

  13. A target has 200 units with binary outcomes. A complete census of the 150 covered units finds all outcomes 0, and the remaining 50 are uncovered. With no other information, what target-mean bound follows?

    Show the answer and reasoning

    The target mean lies in [0,1/4].

    The unknown group contributes between 0 and 50 positive outcomes. Dividing by the known target size 200 gives the bound. Both endpoints can occur with exactly the same covered records, so no frame-only sample enlargement identifies a unique target mean.

  14. A unique nested route has P(C)=1/4, P(S|C)=2/5 and P(R|S,C)=4/5. Is P(C∩S∩R)=2/25 an assumption of mutual independence?

    Show the answer and reasoning

    No; it follows from the conditional-probability chain rule.

    Multiplication of these stated conditional probabilities gives (1/4)(2/5)(4/5)=2/25. Multiplying three unrelated marginal probabilities would instead require justification such as independence. The observed inverse weight is 25/2 only under the declared observation mechanism.

  15. A total estimator has variance 41 and bias −3 for a fixed target. Find its MSE and say whether lower MSE than an unbiased competitor would make it unbiased.

    Show the answer and reasoning

    Its MSE is 41+9=50; a lower MSE would not remove its bias.

    The finite identity is MSE=variance+bias². Squared-error performance and unbiasedness are different properties. Comparing them requires a specified target population, mechanism and loss, not an assertion that either property alone settles every scientific choice.

  16. In a one-unit sample every πᵢ is positive but every distinct-pair probability πᵢⱼ is 0. Is HT total unbiasedness ruled out, and can the usual unbiased pairwise variance formula simply divide by πᵢⱼ?

    Show the answer and reasoning

    Total unbiasedness is not ruled out; the usual pairwise sample variance formula cannot divide by those zero joint probabilities.

    The point-estimator proof uses first-order positivity. Generic estimation of cross-product variance contributions needs information about pairs; a single draw never observes a distinct pair. A known finite population still has a mathematically defined design variance, and additional assumptions or alternatives require separate arguments.

  17. A complete census gives an exposed-minus-unexposed mean difference 3/5. Must this equal the population average causal effect?

    Show the answer and reasoning

    No. Complete coverage does not identify the counterfactual causal contrast or randomize exposure.

    In the stipulated example with Y(1)=Y(0) for every unit, selective exposure creates the association while every causal effect is 0. The descriptive difference is correctly computed; interpreting it causally needs an appropriate design or identification assumptions.

  18. A randomized trial contains only A units. The target also contains B units, and the B treatment effect is unknown. Can weights assigned only to A trial participants identify an arbitrary B effect?

    Show the answer and reasoning

    No; the trial lacks B support, and additional information or scientifically justified cross-group assumptions are needed.

    Randomization can justify a treatment comparison within the trial under its own conditions. It does not reveal missing target-group potential outcomes. A stipulated B effect permits a thought-experiment target average, but that stipulation is not an empirical result from the A-only trial.

What to carry forward

  • A population question needs defined units, eligibility, place, time, outcome and estimand.
  • Target population, sampling frame, selected sample and observed or responding set describe different stages.
  • Record identity and multiplicity affect how frame entries correspond to target units.
  • A probability design specifies the selection mechanism and the relevant positive inclusion probabilities.
  • SRS without replacement makes every fixed-size subset equally likely; equal unit inclusion alone is insufficient.
  • Strata, clusters and multistage paths affect joint selection and precision, even at the same sample size.
  • The HT total is design-unbiased under correct positive inclusion probabilities and observed selected outcomes; independence is not required.
  • A known-size mean and a normalized weighted ratio are different estimators; ratios are not generally exactly unbiased.
  • Realized error, design bias, estimator variance, standard error and MSE have different meanings and units.
  • First-order positivity can suffice for point unbiasedness while zero pair probabilities obstruct the usual unbiased variance estimator.
  • Disproportionate allocation can be intentional; appropriate weights and target denominators are essential.
  • Response adjustment and calibration require auxiliary information and assumptions about what remains unobserved.
  • Larger frame-only samples cannot identify outcomes of target units with zero coverage; useful bounds may remain possible.
  • Conditional multistage probabilities multiply by the chain rule, while estimated response mechanisms add assumptions.
  • Random selection, random treatment assignment, complete descriptive coverage and transfer to another population address distinct questions.
  • Preserve the selection and adjustment history so population, model and causal conclusions can each be assessed against their conditions.

References

Sources for the concepts and teaching approaches in this article.

  1. Statistics Canada2 sources
    1. Selection of a sampleStatistics CanadaStatistics: Power from Data! · §3.2.1: target population, frame and survey unitswww150.statcan.gc.caRead source
    2. Survey Methods and PracticesStatistics CanadaOfficial survey manual · §6.2 and §§7.1–7.3.3; design weights, nonresponse, estimation and precision · PDFwww150.statcan.gc.caRead source
  2. Conservative variance estimation for sampling designs with zero pairwise inclusion probabilitiesPeter M. Aronow and Cyrus SamiiOriginal research · §2 and §§2.1–2.2 (2013); first-order and pairwise positivity have distinct roleswww150.statcan.gc.caRead source
  3. Estimating causal effects from epidemiological dataMiguel A. Hernán and James M. RobinsOriginal methodological article · 2006; observational identification, conditional exchangeability and Appendix A.1 positivitypmc.ncbi.nlm.nih.govRead source
  4. The use of propensity scores to assess the generalizability of results from randomized trialsElizabeth A. Stuart, Stephen R. Cole, Catherine P. Bradshaw and Philip J. LeafOriginal research · abstract inspected; trial participation and target-population scope; full-text access limitedpubmed.ncbi.nlm.nih.govRead source