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Chemistry · Lesson

Heterogeneous catalysis and surface reaction models

Write an explicitly normalized surface mechanism and then add transport constraints. Distinguish site coverage, product events, external film resistance and a porous-pellet effectiveness factor.

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By the end, you can

  • Calculate a mean-field surface turnover on a stated total-site basis.
  • Distinguish product blocking from reverse reaction.
  • Keep intrinsic kinetics, surface concentration and transport-limited observed rates separate.
01

Coverage and the rate basis belong to the mechanism

In a stipulated competitive mean-field Langmuir–Hinshelwood model, both A and B adsorb on equivalent sites. With dimensionless weights w_A=K_Aa_A and w_B=K_Ba_B, vacant fraction is 1/(1+w_A+w_B), and coverages are θ_A=w_A/(1+w_A+w_B) and θ_B=w_B/(1+w_A+w_B). Fast adsorption is treated as quasi-equilibrated; the slower forward reaction has supplied total-site turnover r_site=k_LHθ_Aθ_B.

A different Eley–Rideal model uses one adsorbed reactant and a directly arriving reservoir reactant, with its separately stipulated rate normalization. The same numeric coefficient in two models does not prove a measured performance advantage or identify a real mechanism. Adjacent-site correlations, multisite binding and heterogeneous sites can invalidate a simple product-of-coverages law.

02

More feed can block a needed partner

For a forward-only illustrative pair reaction, set k_LH=4.00 s⁻¹ on the total-site basis and weights w_A=1.00,w_B=2.00. Coverages are 0.250 and 0.500, so turnover is 0.500 product events per total site per second. With accessible site amount 2.00 × 10⁻⁵ mol, the model product rate is 1.00 × 10⁻⁵ mol s⁻¹.

A blocking product weight w_P adds to the denominator. At w_P=4.00, θ_A=0.125, θ_B=0.250 and forward turnover is 0.125 s⁻¹. This example stipulates negligible reverse chemistry; site blocking is not the same mechanism as a reverse reaction. With w_B fixed at 2 and no product weight, turnover 4w_Aw_B/(1+w_A+w_B)² peaks at w_A=3 rather than increasing without limit.

Competitive site occupancy changes a forward event rate
Product weight w_PVacant fractionθ_A; θ_B; θ_PForward turnover / s⁻¹
00.2500.250; 0.500; 00.500
1.000.2000.200; 0.400; 0.2000.320
4.000.1250.125; 0.250; 0.5000.125

Original equivalent-site mean-field competitive adsorption model with w_A=1.00,w_B=2.00 and k_LH=4.00 s⁻¹ on the total-site event basis. Adsorption is quasi-equilibrated; product is a blocking adsorbate and reverse chemistry is stipulated negligible. The table gives model fractions and forward events per total site per second, not measured catalyst performance.

03

The surface can see a different concentration from the bulk

For a nonporous isothermal first-order surface model, external film flux is k_m(c_bulk−c_surface) and intrinsic surface flux is k_s c_surface. Here both coefficients have units m s⁻¹ and use the same external area. At no accumulation, equate these fluxes rather than insert the bulk concentration into the intrinsic expression automatically.

The result is c_surface=k_m c_bulk/(k_m+k_s) and k_overall=(1/k_m+1/k_s)⁻¹. If film transport is slow, increasing intrinsic surface speed can have a limited effect on the observed flux. A mass-based coefficient requires conversion with the relevant specific area; heat and internal-pore effects would require additional balances.

04

An internal diffusion model introduces another convention

For a uniform spherical isothermal first-order pellet, define φ=R_p√(k_v/D_e), with pellet radius R_p, intrinsic volume-normalized coefficient k_v in s⁻¹ and effective diffusivity D_e in m² s⁻¹. The effectiveness is η_eff=3(φ cothφ−1)/φ² relative to the entire pellet at its outer-surface concentration. Its limit approaches 1 as φ approaches 0.

For this specific model, η_eff≤1. Nonisothermal or other kinetic models need different conclusions. The surface concentration is not necessarily the bulk concentration, and an observed apparent coefficient is not the intrinsic k_v. A source convention based on R_p/3 would give a parameter three times smaller; its formula must be converted consistently rather than combined with this radius convention.

Worked examples

Convert a site-normalized turnover into an amount rate

Use the specified w_A=1.00,w_B=2.00,w_P=0,k_LH=4.00 s⁻¹ and accessible site amount 2.00 × 10⁻⁵ mol. Find forward product rate.

  1. The shared site denominator is 1+1+2=4.
  2. θ_A=1/4 and θ_B=2/4.
  3. Turnover=4.00 ×(1/4)×(1/2)=0.500 s⁻¹.
  4. Multiply by the stipulated total accessible site amount.

Forward amount rate=1.00 × 10⁻⁵ mol s⁻¹. The site normalization and mean-field pair assumptions are essential.

Solve compatible film and surface resistances

Use stipulated k_m=0.0200 m s⁻¹,k_s=0.0800 m s⁻¹,c_bulk=2.00 mol m⁻³ and external area 0.0100 m². Find surface concentration, flux and amount rate.

  1. c_surface=k_m c_bulk/(k_m+k_s)=0.400 mol m⁻³.
  2. k_overall=k_m k_s/(k_m+k_s)=0.0160 m s⁻¹.
  3. Flux=k_overall c_bulk=0.0320 mol m⁻² s⁻¹.
  4. Amount rate=flux×area=0.000320 mol s⁻¹.

c_surface=0.400 mol m⁻³ and observed amount rate=3.20 × 10⁻⁴ mol s⁻¹. Assuming c_surface=c_bulk would overestimate the intrinsic-area flux here.

State the pellet radius convention

For the stipulated uniform spherical isothermal first-order model, use R_p=1.00 × 10⁻³ m,k_v=0.0100 s⁻¹ and D_e=1.00 × 10⁻⁹ m² s⁻¹. Find φ and η_eff.

  1. φ=R_p√(k_v/D_e)=√10≈ 3.16228.
  2. Use the radius-convention expression η_eff=3(φ cothφ−1)/φ².
  3. The supplied model gives approximately 0.652089.
  4. The reference is a pellet uniformly at its outer-surface concentration, not automatically at the bulk concentration.

φ≈ 3.16 and η_eff≈ 0.652. This is the specified isothermal first-order effectiveness model, not a universal catalyst efficiency.

Try it yourself

  1. A turnover of 0.500 s⁻¹ acts on 2.00 × 10⁻⁵ mol of accessible sites. What amount rate follows on that basis?

    Show the answer and reasoning

    1.00 × 10⁻⁵ mol s⁻¹.

    Multiply turnover by its defined site amount.

  2. Is competitive product blocking the same assumption as a reverse chemical event?

    Show the answer and reasoning

    No.

    Adsorption occupancy and reaction direction are separate parts of the mechanism.

  3. Can an m s⁻¹ film coefficient be combined directly with an unrelated mass-normalized catalyst coefficient?

    Show the answer and reasoning

    No.

    Their area and amount bases must be converted consistently.

  4. Does η_eff≤1 hold for every nonisothermal catalytic system?

    Show the answer and reasoning

    No.

    That bound here belongs to the specified uniform isothermal first-order pellet.

What to carry forward

  • Define sites, coverage and event normalization.
  • A compatible rate law does not uniquely identify a mechanism.
  • Transport can separate bulk and surface conditions.
  • Effectiveness depends on geometry, coefficient basis and model assumptions.

References

Teaching resources and reference material supporting this lesson’s explanations and examples.

  1. IIT Guwahati, Department of Chemical Engineering; NPTEL joint IIT/IISc programme2 sources
    1. Module7 Lecture1: Interfacial Reactions IPallab GhoshSource · PDFarchive.nptel.ac.inRead source
    2. Module7 Lecture2: Interfacial Reactions II, internal transportPallab GhoshSource · PDFarchive.nptel.ac.inRead source
  2. Technical note: Adsorption/desorption equilibria and rates from transition state theoryDaniel A. Knopf; Markus AmmannSourceacp.copernicus.orgRead source
  3. Molecular Systems Biology Lecture5: Metabolic Control AnalysisJohann Rohwer (lectures); Dawie van Niekerk (tutorials/data analysis); Jacky Snoep (tutorials/practical)Source · PDFglue.jjj.sun.ac.zaRead source