Chemistry · Lesson
Heterogeneous catalysis and surface reaction models
Write an explicitly normalized surface mechanism and then add transport constraints. Distinguish site coverage, product events, external film resistance and a porous-pellet effectiveness factor.
Back to the Chemistry mapBy the end, you can
- Calculate a mean-field surface turnover on a stated total-site basis.
- Distinguish product blocking from reverse reaction.
- Keep intrinsic kinetics, surface concentration and transport-limited observed rates separate.
Coverage and the rate basis belong to the mechanism
In a stipulated competitive mean-field Langmuir–Hinshelwood model, both A and B adsorb on equivalent sites. With dimensionless weights w_A=K_Aa_A and w_B=K_Ba_B, vacant fraction is 1/(1+w_A+w_B), and coverages are θ_A=w_A/(1+w_A+w_B) and θ_B=w_B/(1+w_A+w_B). Fast adsorption is treated as quasi-equilibrated; the slower forward reaction has supplied total-site turnover r_site=k_LHθ_Aθ_B.
A different Eley–Rideal model uses one adsorbed reactant and a directly arriving reservoir reactant, with its separately stipulated rate normalization. The same numeric coefficient in two models does not prove a measured performance advantage or identify a real mechanism. Adjacent-site correlations, multisite binding and heterogeneous sites can invalidate a simple product-of-coverages law.
More feed can block a needed partner
For a forward-only illustrative pair reaction, set k_LH=4.00 s⁻¹ on the total-site basis and weights w_A=1.00,w_B=2.00. Coverages are 0.250 and 0.500, so turnover is 0.500 product events per total site per second. With accessible site amount 2.00 × 10⁻⁵ mol, the model product rate is 1.00 × 10⁻⁵ mol s⁻¹.
A blocking product weight w_P adds to the denominator. At w_P=4.00, θ_A=0.125, θ_B=0.250 and forward turnover is 0.125 s⁻¹. This example stipulates negligible reverse chemistry; site blocking is not the same mechanism as a reverse reaction. With w_B fixed at 2 and no product weight, turnover 4w_Aw_B/(1+w_A+w_B)² peaks at w_A=3 rather than increasing without limit.
| Product weight w_P | Vacant fraction | θ_A; θ_B; θ_P | Forward turnover / s⁻¹ |
|---|---|---|---|
| 0 | 0.250 | 0.250; 0.500; 0 | 0.500 |
| 1.00 | 0.200 | 0.200; 0.400; 0.200 | 0.320 |
| 4.00 | 0.125 | 0.125; 0.250; 0.500 | 0.125 |
Original equivalent-site mean-field competitive adsorption model with w_A=1.00,w_B=2.00 and k_LH=4.00 s⁻¹ on the total-site event basis. Adsorption is quasi-equilibrated; product is a blocking adsorbate and reverse chemistry is stipulated negligible. The table gives model fractions and forward events per total site per second, not measured catalyst performance.
The surface can see a different concentration from the bulk
For a nonporous isothermal first-order surface model, external film flux is k_m(c_bulk−c_surface) and intrinsic surface flux is k_s c_surface. Here both coefficients have units m s⁻¹ and use the same external area. At no accumulation, equate these fluxes rather than insert the bulk concentration into the intrinsic expression automatically.
The result is c_surface=k_m c_bulk/(k_m+k_s) and k_overall=(1/k_m+1/k_s)⁻¹. If film transport is slow, increasing intrinsic surface speed can have a limited effect on the observed flux. A mass-based coefficient requires conversion with the relevant specific area; heat and internal-pore effects would require additional balances.
An internal diffusion model introduces another convention
For a uniform spherical isothermal first-order pellet, define φ=R_p√(k_v/D_e), with pellet radius R_p, intrinsic volume-normalized coefficient k_v in s⁻¹ and effective diffusivity D_e in m² s⁻¹. The effectiveness is η_eff=3(φ cothφ−1)/φ² relative to the entire pellet at its outer-surface concentration. Its limit approaches 1 as φ approaches 0.
For this specific model, η_eff≤1. Nonisothermal or other kinetic models need different conclusions. The surface concentration is not necessarily the bulk concentration, and an observed apparent coefficient is not the intrinsic k_v. A source convention based on R_p/3 would give a parameter three times smaller; its formula must be converted consistently rather than combined with this radius convention.
Worked examples
Convert a site-normalized turnover into an amount rate
Use the specified w_A=1.00,w_B=2.00,w_P=0,k_LH=4.00 s⁻¹ and accessible site amount 2.00 × 10⁻⁵ mol. Find forward product rate.
- The shared site denominator is 1+1+2=4.
- θ_A=1/4 and θ_B=2/4.
- Turnover=4.00 ×(1/4)×(1/2)=0.500 s⁻¹.
- Multiply by the stipulated total accessible site amount.
Forward amount rate=1.00 × 10⁻⁵ mol s⁻¹. The site normalization and mean-field pair assumptions are essential.
Solve compatible film and surface resistances
Use stipulated k_m=0.0200 m s⁻¹,k_s=0.0800 m s⁻¹,c_bulk=2.00 mol m⁻³ and external area 0.0100 m². Find surface concentration, flux and amount rate.
- c_surface=k_m c_bulk/(k_m+k_s)=0.400 mol m⁻³.
- k_overall=k_m k_s/(k_m+k_s)=0.0160 m s⁻¹.
- Flux=k_overall c_bulk=0.0320 mol m⁻² s⁻¹.
- Amount rate=flux×area=0.000320 mol s⁻¹.
c_surface=0.400 mol m⁻³ and observed amount rate=3.20 × 10⁻⁴ mol s⁻¹. Assuming c_surface=c_bulk would overestimate the intrinsic-area flux here.
State the pellet radius convention
For the stipulated uniform spherical isothermal first-order model, use R_p=1.00 × 10⁻³ m,k_v=0.0100 s⁻¹ and D_e=1.00 × 10⁻⁹ m² s⁻¹. Find φ and η_eff.
- φ=R_p√(k_v/D_e)=√10≈ 3.16228.
- Use the radius-convention expression η_eff=3(φ cothφ−1)/φ².
- The supplied model gives approximately 0.652089.
- The reference is a pellet uniformly at its outer-surface concentration, not automatically at the bulk concentration.
φ≈ 3.16 and η_eff≈ 0.652. This is the specified isothermal first-order effectiveness model, not a universal catalyst efficiency.
Try it yourself
A turnover of 0.500 s⁻¹ acts on 2.00 × 10⁻⁵ mol of accessible sites. What amount rate follows on that basis?
Show the answer and reasoning
1.00 × 10⁻⁵ mol s⁻¹.
Multiply turnover by its defined site amount.
Is competitive product blocking the same assumption as a reverse chemical event?
Show the answer and reasoning
No.
Adsorption occupancy and reaction direction are separate parts of the mechanism.
Can an m s⁻¹ film coefficient be combined directly with an unrelated mass-normalized catalyst coefficient?
Show the answer and reasoning
No.
Their area and amount bases must be converted consistently.
Does η_eff≤1 hold for every nonisothermal catalytic system?
Show the answer and reasoning
No.
That bound here belongs to the specified uniform isothermal first-order pellet.
What to carry forward
- Define sites, coverage and event normalization.
- A compatible rate law does not uniquely identify a mechanism.
- Transport can separate bulk and surface conditions.
- Effectiveness depends on geometry, coefficient basis and model assumptions.
References
Teaching resources and reference material supporting this lesson’s explanations and examples.
IIT Guwahati, Department of Chemical Engineering; NPTEL joint IIT/IISc programme2 sources
- Technical note: Adsorption/desorption equilibria and rates from transition state theoryDaniel A. Knopf; Markus AmmannSource
- Molecular Systems Biology Lecture5: Metabolic Control AnalysisJohann Rohwer (lectures); Dawie van Niekerk (tutorials/data analysis); Jacky Snoep (tutorials/practical)Source · PDF